Answer : The value of standard free energy is, -152.4 kJ/mol
Explanation :
The given balanced cell reaction is:
The half reaction will be:
Reaction at anode (oxidation) :
Reaction at cathode (reduction) :
First we have to calculate the standard electrode potential of the cell.
Relationship between standard Gibbs free energy and standard electrode potential follows:
where,
= standard free energy = ?
n = number of electrons transferred = 2
F = Faraday constant =
= standard electrode potential of the cell = 0.79 V
Now put all the given values in the above formula, we get:
Therefore, the value of standard free energy is, -152.4 kJ/mol