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tresset_1 [31]
3 years ago
12

Read each description below. Choose the force diagram (free-body diagram) that best represents the description. You may neglect

the effects of air resistance. |
A. Mark's physics book is on the desk. Mark pushes horizontally (from the side) on the book, but the book does not move. |
B. Kendall's physics book is on the desk. Kendall pushes horizontally (from the side) on the book, and the book moves across the desk at a constant speed. |
C. Jenny pushes a cart at constant velocity down the grocery store aisle. |
D. Eddy is driving his Camaro down a straight, level road while on cruise control. |
E. Ryan is accelerating his Dakota down a straight, level road. |
F. Jackie's Viper is parked on the shoulder of the road while she changes a flat tire. |

Physics
1 answer:
Papessa [141]3 years ago
5 0
A. Diagram A
B. Diagram C & D
C. Diagram B
D. Diagram C & D
E. Diagram B
F. Diagram C & D
These are simplified representations of an object's body and the force vectors acting on it. Some of the main forces that are involve are normal force, friction, push or pull and gravity.
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Carlota does 2000 J of work on a machine. The machine does 500 J of work. What is the efficiency of the machine?
Luden [163]
A. 4% you divide 2000 to 500 and you get 4 which is your answer
3 0
3 years ago
a person can throw a 300 gram ball at 25 m/s the maximum height the person can throw the ball on Earth?​
jolli1 [7]

Answer:

Elevation =31.85[m]

Explanation:

We can solve this problem by using the principle of energy conservation. This consists of transforming kinetic energy into potential energy or vice versa. For this specific case is the transformation of kinetic energy to potential energy.

We need to first identify all the input data, and establish a condition or a point where the potential energy is zero.

The point where the ball is thrown shall be taken as a reference point of potential energy.

E_{p} = E_{k} \\where:\\E_{p}= potential energy [J]\\ E_{k}= kinetic energy [J]

m = mass of the ball = 300 [gr] = 0.3 [kg]

v = initial velocity = 25 [m/s]

E_{k}=\frac{1}{2}  * m* v^{2} \\E_{k}= \frac{1}{2} * 0.3* (25)^{2} \\E_{k}= 93.75 [J]

93.75=m*g*h\\where:\\g = gravity = 9.81 [m/s^2]\\h = elevation [m]\\replacing\\h=\frac{E_{k}}{m*g} \\h=\frac{93.75}{.3*9.81} \\h=31.85[m]

5 0
4 years ago
A car slows down uniformly from a speed of 22 m/s to rest in 4.0 seconds. How far did it travel in that time
krek1111 [17]

Answer:

\boxed{\sf Distance \ travelled = 44 \ m}

Given:

Initial speed (u) = 22 m/s

Final speed (v) = 0 m/s (Rest)

Time taken (t) = 4 seconds

To Find:

Distance travelled by car (s)

Explanation:

From equation of motion of object moving with uniform acceleration in straight line we have:

\boxed{ \bold{s =  (\frac{v + u}{2} )t}}

By substituting value of v, u & t in the equation we get:

\sf \implies s = ( \frac{0 + 22}{2} ) \times 4 \\  \\  \sf \implies s =  \frac{22}{2}  \times 4 \\  \\  \sf \implies s = 11 \times 4 \\  \\  \sf \implies s = 44 \: m

\therefore

Distance travelled by car (s) = 44 m

4 0
4 years ago
Write the first equation of motion. Under what condition(s) is this equation valid?​
Zepler [3.9K]

Explanation:

The first equation of motion in kinematics is given by :

v=u+at .....(1)

u is initial speed

a is acceleration

v is final speed

t is time

Equation (1) is valid when the object is moving with constant acceleration. This equation gives relation between velocity and time.

3 0
3 years ago
(30 points) Air at 500 kPa and 400 K enters an adiabatic nozzle at a velocity of 30 m/s and leaves at 300 kPa and 350 K. Using v
Sophie [7]

Answer:

Explanation:

Check attachment for solution

8 0
3 years ago
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