At high temperature the gas would diffuse out as the pressure increases and at extremely low temperature the solid becomes compact.
Explanation:
The states of matter largely depends on the temperature. Any substance when crosses the threshold temperature its phase changes.
When temperature is low the motion of molecules is also low and internal energy also gets low. Solid have tendency of settling in low energy level and have highly compact molecules. At low temperature the solid would compress as molecules would be highly condensed.
Gas in the nature has its molecules quite far apart in matter. According to Kinetic theory of gases the increase in temperature causes rapid collisions of the gas molecule as the kinetic energy of molecules increases. The greater force of collision would cause increase in pressure of the container and increased diffusion rate.
We use the Boyle's law to solve this question. At constant temperature, the volume of a fixed mass of a gas is inversely proportional to its pressure. When comparing the fixed mass of gas at different conditions under this law, the expression below is used.
P₁V₁=P₂V₂
P₁=5.0 atm
P₂=7.0atm
V₁=3.5 L
V₂=V
5.0×3.5=7.0×V
V= (5.0×3.5)7.0
V=2.5 L
Calculate the heat gained by the water first.
q = mCpΔT
m = 20.0 g
Cp = 4.186 J/g°C
ΔT = T(final) - T(initial) = 15.0°C - 10.0°C = 5.0°C
q = (20.0)(4.186)(5.0) = 419 J
This is equal to the heat lost by the metal, so calculate Cp for the metal, given:
q = -419 J (negative because heat was lost)
m = 5.00 g
ΔT = 15.0°C - 100.0°C = -85.0°C (negative because the temperature decreased)
q = mCpΔT —> Solve for Cp —> Cp = q/mΔT
Cp = -419 / (5.00 • -85.0) = 0.986 J/g°C