1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Eduardwww [97]
3 years ago
13

Hydrogen bond is not formed by 1) oxygen 2) nitrogen 3) chlorine

Chemistry
1 answer:
Viktor [21]3 years ago
5 0

Answer:

Chlorine

Explanation:

Even though chlorine is highly electronegative, the best answer is no, and in this class we will consider chlorine not to form hydrogen bonds (even though it has the same electronegativity as oxygen). This is because chlorine is large and its lone electron is in a diffuse orbital, covering a large area, and thus do not have the high charge density to act as a strong hydrogen bond acceptor. But it does form weak hydrogen bonds in solid crystalline hydrogen chloride at very low temperatures.

You might be interested in
Relation between glancing and angle of deviation<br>​
shtirl [24]

Answer:

the Glancing angle is the angle between the incident ray and plane mirror which is 90o in the given case. The angle between the direction of the incident ray and the reflected ray is the angle of deviation. Since the angle of deviation for a plane mirror is twice the glancing angle, the angle of deviation is 1800.

5 0
3 years ago
The following reaction produces ethanoic acid (CHACOOH) from methanol (CH3OH) and carbon
tigry1 [53]

Answer:

\boxed{\text{300 g}}

Explanation:

We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.

M_r:         32                          60

           CH₃OH + CO ⟶ CH₃COOH

m/g:        160

(a) Moles of CH₃OH

\text{Moles of CH$_{3}$OH} = \text{160 g CH$_{3}$OH }\times \dfrac{\text{1 mol CH$_{3}$OH }}{\text{32 g CH$_{3}$OH}}= \text{5.00 mol CH$_{3}$OH}

(b) Moles of CH₃COOH

\text{Moles of CH$_{3}$COOH} = \text{5.00 mol CH$_{3}$OH } \times \dfrac{\text{1 mol CH$_{3}$COOH}}{\text{1 mol CH$_{3}$OH }} = \text{5.00 mol CH$_{3}$COOH}

(c) Mass of CH₃COOH

\text{Mass of CH$_{3}$COOH} =\text{5.00 mol CH$_{3}$COOH} \times \dfrac{\text{60 g CH$_{3}$COOH}}{\text{1 mol CH$_{3}$COOH}} = \textbf{300 g CH$_{3}$COOH}\\\\\text{The maximum mass of ethanoic acid that can be produced is $\boxed{\textbf{300 g}}$}

3 0
4 years ago
Automobile bodies contain significant amounts of iron. The iron is protected by the addition of zinc. This is called galvanizati
Oksana_A [137]

<u>Answer:</u> The balanced chemical equation is written below.

<u>Explanation:</u>

Galvanization is defined as the process in which a protective layer of zinc is applied to iron or steel to prevent the metal from rusting.

Zinc prevents the oxidation of iron and acts as a reducing agent in the process.

The half reaction for the process follows:

<u>Oxidation half reaction:</u>  Zn\rightarrow Zn^{2+}+2e^-

<u>Reduction half reaction:</u>  Fe^{2+}+2e^-\rightarrow Fe

Net chemical equation:  Zn+Fe^{2+}\rightarrow Zn^{2+}+Fe

Hence, the balanced chemical equation is written above.

6 0
3 years ago
The bulb lights up in the circuit. Only two rods are conductors of electricity. Which one of the rods, X, Y or Z is definitely a
meriva

Answer: Rod X.

Explanation:

Ok, the electricity starts in the top left part. First, it must travel in the X rod, then it keeps traveling until it reaches the parallel path, and it can go to the Z rod, to the Y rod, or to both of them, and then it reaches the bulb (the circle with a X inside of it).

We know that two rods are conductors of electricity.

Now, suppose the case where rods Z and Y are the ones that conduct electricity, this means that X does not conduct electricity, then when the current reaches to X it stops (because X does not conduct) then the electricity never reaches the rods Z and Y, and then the electricity never reaches the bulb, but we know that the bulb lights up, so we must have that X is one of the conducting rods.

Then, if for example, Y does not conduct electricity, the electricity still can run through the Z rod and eventually reach the bulb.

So we can conclude that the rod that is definitely a conductor of electricity is rod X

4 0
3 years ago
What volume of a 2.25 M sodium chloride solution will contain 4.58 moles of sodium chloride
Rzqust [24]

Answer:

Option E. 2.04 L

Explanation:

Data obtained from the question include:

Molarity of NaCl = 2.25 M

Mole of NaCl = 4.58 moles

Volume =..?

Molarity is simply defined as the mole of solute per unit litre of the solution. It is represented mathematically as:

Molarity = mole /Volume

With the above formula, we can obtain the volume of the solution as follow:

Molarity = mole /Volume

2.25 = 4.58/volume

Cross multiply

2.25 x volume = 4.58

Divide both side by 2.25

Volume = 4.58/2.25

Volume = 2.04 L

Therefore, the volume of the solution is 2.04 L

6 0
3 years ago
Other questions:
  • Consider a solution consisting of the following two buffer systems:
    13·1 answer
  • Ethers are almost always used as solvents for Grignard reactions, all of the reasons why they work so well are not fully underst
    7·1 answer
  • A break in the crust where slabs slip past each other is a(n)
    14·1 answer
  • Why can salt and sugar both dissolve in water, even though one is ionic and the other is covalent?
    5·2 answers
  • Calculate the molar mass of NH4NO3.
    14·1 answer
  • Which of the following statements is true about energy quantization at the atomic level? Electrons in the outermost orbits are t
    11·1 answer
  • I am a beginner can someone give me a brainliest to start me out I would appreciate it.<br> :)
    10·2 answers
  • Free points lol happy April fools day
    5·2 answers
  • C. What is Cytoplasm? What does it contain?​
    10·1 answer
  • the ___is the area that allows us to pinpoint the location of pain, identify a texture and be aware of how our limbs are positio
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!