Answer:
Cl2 + 2NaBr --> 2NaCl + Br2
Explanation:
This is a single displacement reaction where one side of the ionic compound switches with the other.
So, Cl2 + NaBr ---> NaCl + Br2
This isolates the Bromine and puts the Chlorine in it's place.
Then, balance out the equation like so and you should get
Cl2 + 2NaBr --> 2NaCl + Br2
Answer:
In order to balance the chemical equation, you need to make sure the number of atoms of each element on the reactants side is equal to the number of atoms of each element on the product side. In order make both sides equal, you will need to multiply the number of atoms in each element until both sides are equal.
Hope this helped you.
Answer:
dipole-dipole forces, ion-dipole forces, higher molar mass, hydrogen bonding, stronger intermolecular forces
Explanation:
<em>1. H₂S and H₂Se exhibit the following intermolecular forces: </em><em>dipole-dipole forces </em><em>and </em><em>ion-dipole forces</em><em>.</em> These molecules have a bent geometry, thus, a dipolar moment which makes them dipoles. When they are in the aqueous form they are weak electrolytes whose ions interact with the water dipoles
<em>2. Therefore, when comparing H₂S and H₂Se the one with a </em><em>higher molar mass</em><em> has a higher boiling point.</em> In this case, H₂Se has a higher boiling point than H₂S due to its higher molar mass.
<em>3. The strongest intermolecular force exhibited by H₂O is </em><em>hydrogen bonding</em><em>. </em>This is a specially strong dipole-dipole interaction in which the positive density charge on the hydrogens is attracted to the negative density charge on the oxygen.
<em>4. Therefore, when comparing H₂Se and H₂O the one with </em><em>stronger intermolecular forces</em><em> has a higher boiling point. </em>That's why the boiling point of H₂O is much higher than the boiling point of H₂Se.
Answer:
C
Explanation:
Well movement is, reproduction is, responsiveness is, metabolism is, so accumulation would be the answer.
