How is the average American diet affected by our current food system?"

1 answer:

8 0

Poor diet is predominantly associated with weight gain and obesity; however, the harmful effects do not end there. Animal and human studies indicate that an unhealthy diet can contribute to the development of many diseases, like cardiovascular disease and cancer, and can even affect the brain.

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A person on a road trip drives a car at different constant speeds over several legs of the trip. She drives for 10.0 min at 50.0

irakobra [83]

<h2>The average speed for the entire trip is 47.5 m/s .</h2>

It is given that for different time span car have different speed and also the person spend $40\ min=\dfrac{40}{60}\ hrs =0.67\ hrs\ .$ in eating lunch and buying gas.

We know , average speed is total distance covered by total time taken .

Therefore , average speed , $v=\dfrac{total\ distance }{total\ times}$

$v=\dfrac{\dfrac{10}{60}\times 50+\dfrac{19}{60}\times 100+\dfrac{60}{60}\times 55}{\dfrac{10}{60}+\dfrac{10}{60}+\dfrac{60}{60}+ \dfrac{40}{60}}\\\\\\v=47.5\ m/s$

Hence, this is the required solution.

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3 years ago

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GREYUIT [131]

Solid because the particles vibrate in place

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3 years ago

Davisson and Germer performed their experiment with a nickel target for several electron bombarding energies. At what angles wou

pochemuha

Answer:

The angle of diffraction are 67.75 deg and 53.57 deg.

Explanation:

Given:

Davisson and Germer experiment with nickel target for electrons bombarding.

Voltages : $38\ eV$ and $54\ eV$

We have to find the angles that is $\phi_3_8$ and $\phi_5_4$ .

Concept:

Davison Germer experiment is based on de Broglie hypothesis where it says matter has both wave and particle nature.
When electrons get reflected from the surface of a metal target with an atomic spacing of $D$ , they form diffraction patterns.
The positions of diffraction maxima are given by $Dsin(\phi) = n\lambda$ .
An atomic spacing is $D = 0.215\ nm$ , when the principal maximum corresponds to n=1
The wavelength is $\lambda$ , and $\lambda =\frac{1.227 \sqrt{V} } {\sqrt{V_o}}\ nm$ .