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Mariana [72]
2 years ago
11

A race car has a mass of 710 kg. It starts from rest and travels 40 m in 3.0 s. The car is uniformly accelerated during the enti

re time. What net force is applied to it
Physics
1 answer:
Archy [21]2 years ago
6 0

The net force applied to it is 6311.9 N.

To calculate the net force to the car, first, we need to find the acceleration using the equation of motion.

Force: This as be defined as the product of mass and acceleration of a body. The S.I unit of force is Newton (N)

⇒ Formula

  • S = ut+at²/2................. Equation 1

⇒ Where:

  • u = Initial velocity
  • S = Distance
  • t = Time
  • a = acceleration

From the question,

 ⇒Given:

  • S = 40 m
  • t = 3.0 s
  • u = 0 m/s (at rest)

⇒ Substitute these values into equation 1

  • 40 = 0(3)+a(3²)/2

⇒ Solve for a

  • 9a = 80
  • a = 80/9
  • a = 8.89 m/s²

⇒ To get the force, we use the formula below

  • F = ma    .................... Equation 2

⇒ Where:

  • F = Force applied
  • m = mass of the car

⇒ Given:

  • m = 710 kg
  • a = 8.89 m/s²

⇒ Substitute these values into equation 2

  • F = 710(8.89)
  • F = 6311.9 N

Hence the net force applied to it is 6311.9 N.

Learn more about force here: brainly.com/question/13370981

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What does the outer part of the disk turn into?
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Answer:

what does the outer part of the disk turn into

Explanation:

4) it gets sucked into the star

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a 60kg rock in on a mountain in banff national park breaks free from a ledge and falls down 500 meters to the bottom of the moun
stellarik [79]
Using Newton's law that  F = ma.

The force here is the net force.  The forces acting in opposite direction are the weight and the air resistance. The weight of course is acting downwards and the air  resistance is pushing upwards.

Therefore:

W -  AR  = ma                    W = Weight = mg,  AR = Air Resistance = 150.
                                           g = 10 m/s2
mg  - AR  = ma

60(10) - 150 = 60a
600  -  150   = 60a
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Cheers.

5 0
3 years ago
a delivery truck travels 18 blocks north, 10 blocks east, and 16 blocks south. what is the distance traveled and displacement. ​
AleksAgata [21]

1) Distance: 44 blocks

2) Displacement: 10.2 blocks at 11.3^{\circ} north of east

Explanation:

1)

- Distance is a scalar quantity that gives a measure of the total length of the path travelled by an object, regardless of its direction

- Displacement is a vector quantity which connects the initial position to the final position of motion of the object. Being a vector, it has both magnitude and direction: the magnitude is the shortest distance between initial and final position, while the direction goes from the initial to the final position.

In this problem, the motion is:

18 blocks north

10 blocks east

16 blocks south

So, the distance is the sum of the distances covered in each part:

distance = 18 + 10 + 16 = 44 blocks

2)

The displacement can be calculated by evaluating the initial and the final position. Along the north-south direction, the displacement is

d_y = 18 (n) - 16 (s) = 2 blocks north

Along the east-west direction,

d_x=10 blocks east)

So, the magnitude of the displacement is given by Pythagorean's theorem

d=\sqrt{d_x^2+d_y^2}=\sqrt{2^2+10^2}=10.2 blocks

And the direction is given by

\theta=tan^{-1}(\frac{d_y}{d_x})=tan^{-1}(\frac{2}{10})=11.3^{\circ}

measured as north of east.

Learn more about distance and displacement:

brainly.com/question/3969582

#LearnwithBrainly

8 0
3 years ago
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