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Natali5045456 [20]
3 years ago
10

Objects that gain elastic energy by being stretched out

Physics
1 answer:
Monica [59]3 years ago
6 0
Rubber band, elastic, spring
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How could infrared imaging be used to find a lost hiker? Answer in 2-3 complete sentences.
Tamiku [17]

When you scan the hiker's body, you will notice a warm spot. Unless that person was dead, they would not be emitting heat.

<h3>What is hiking?</h3>
  • According to Smokymountains.com, which examined more than 100 news reports of missing hikers, getting off the trail is the most common reason people get lost.
  • That is not someone you want to be. Once you're on the trail, you can use the GPS to ensure you're on the right track.
  • You can take it a step further by bringing a device like a Garmin IN Reach with you on the trail. This GPS also functions as a satellite communicator.
  • Whereas hiking includes the word "walk," which is typically seen as jovial, easy, and pleasant, trekking is defined as a "journey," which is typically more difficult, requires more effort, and takes more than one day.

To learn more about hiker, refer to:

brainly.com/question/26614004

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3 0
1 year ago
The velocity of a particle traveling in a straight line is given by v = (6t - 3t²) m/s, where t is in seconds. If s = 0 when t =
qaws [65]

Answer

given,

v = (6 t - 3 t²) m/s

we know,

v = \dfrac{dx}{dt}

a = \dfrac{dv}{dt}

position of the particle

dx = v dt

integrating both side

\int dx = (6t - 3 t^2)\int dt

 x = 3 t² - t³

Position of the particle at t= 3 s

 x = 3  x 3² - 3³

 x = 0 m

now, particle’s deceleration

a = \dfrac{dv}{dt}

a = \dfrac{d}{dt}(6t - 3 t^2)

  a = 6 - 6 t

at t= 3 s

    a = 6 - 6 x 3

    a = -12 m/s²

distance traveled by the particle

  x = 3 t² - t³

at t = 0 x = 0

   t = 1 s   , x = 3 (1)² - 1³ = 2 m

   t = 2 s  ,  x = 3(2)² - 2³ = 4 m

   t = 3 s ,   x =  0 m

total distance traveled by the particle

D = distance in 0-1 s + distance in 1 -2 s + distance in 2 -3 s

D = 2 + 4 + 2 = 8 m

average speed of the particle

v_{avg} = \dfrac{distance}{time}

v_{avg} = \dfrac{8}{3}

v_{avg} =2.67\ m/s

8 0
3 years ago
Is dimensionally correct equation must be physically correct . Explain your logic behind physically correct equation ?​​
anyanavicka [17]
An equation can be dimensionally correct but that does not mean that it is physically correct. Explanation is given in the photo.

8 0
1 year ago
A wave is traveling at a speed of
Digiron [165]
Answer: 5Hz
Explanation: Frequency = Wave speed divided by wavelength.
3 0
3 years ago
What type of chemical equation is represented in the following 2KCl + Pb(NO3)2 → 2 KNO3 + PbCl2
UNO [17]
If your talking about the chemical equations like combustion, single displacement, etc. Then the equation would be double displacement:
AB + CD ---> AD + CB
6 0
3 years ago
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