What is the speed of an electron that has been accelerated from rest through a potential difference of 1020 V?
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Answer:
r = 9.92 mm
Explanation:
Given that,
Mass of oil drop,
It acquires 2 surplus electrons, q = +2e
Potential difference, V = 620 V
Thie potential difference is applied between the pair of horizontal metal plates the drop is in equilibrium.
We need to find the distance between the plates.
At equilibrium,
mg = qE
Since, E = V/r (r is distance between plates)
So, the distance between the plates is 9.92 mm.