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ollegr [7]
3 years ago
8

What is a device that minimizes the force on a microscopic object during a collision?

Physics
1 answer:
liraira [26]3 years ago
3 0
An impact which stops a moving object must do enough work to take away its kinetic energy, so extending the distance moved during the collision reduces the impact force.
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Give an example of a compound machine. Explain how at least two simple machines are part of the complex machine. Thank you !!
kaheart [24]

A compound machine is a combination of at least two simple machines. Simple machines can be a lever, a wedge, a while + axle, an incline plane, a pulley, and a screw.

There are many examples of compound machines. One of them is a showel that combines a wedge (the scoop part of shovel) and a lever (the handle to transfer the force to lift).

A much more complex compound machine is a bicycle, comprising simple machines ranging from wheels and axles, to screws, and levers (think of the pedals).

5 0
3 years ago
The courtroom role that possesses the most discretion is?
KonstantinChe [14]
The role of the Prosecutor's
5 0
3 years ago
A manometer using oil (density 0.900 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases
Mila [183]

Answer:

Rise in level of fluid is 0.11 m

Rise in level of fluid in case of mercury is 0.728 cm or 7.28 mm

Solution:

As per the question:

Density of oil, \rho_{o} = 0.900\ g/cm^{3} = 900\ kg/m^{3}

Change in Pressure in the tank, \Delta P = 7.28\ mmHg

Density of the mercury, \rho_{m} = 13.6\ g/cm^{3} = 13600\ kg/m^{3}

Now,

To calculate the rise in the level of fluid inside the manometer:

We know that:

1 mmHg = 133.332 Pa

Thus

\Delta P = 7.28\ times 133.332 = 970.656\ Pa

Also,

\Delta P = \rho_{o} gh

where

g = acceleration due to gravity

h = height of the fluid level

970.656 = 900\times 9.8\times h

h = 0.11 m

Now, if mercury is used:

\Delta P = \rho_{m} gh

970.656 = 13600\times 9.8\times h

h = 0.00728 m = 7.28 mm

3 0
3 years ago
Atruck with a mass of 5280 Kg has an acceleration of 45 m/s/s what is the force acting on the truck?
horrorfan [7]
117.3 I think that’s it mb if that wrong
8 0
3 years ago
The magnitude of the drag force of air resistance on a certain 20kg object is proportional to its speed. If the object has a ter
Anna11 [10]
Given:
object = 20kg
terminal speed of object = 80 m/s

According to the problem, drag force is proportional to speed, so Fd = kv ; k is some constant
At terminal velocity Vt: Fg = Fdmg = kVtk = mg / Vt = (20.0)(9.8)/(80.0) = 2.45 kg/s
<span>Fd = kv = 2.45v</span>
Fd = 2.45 (30.0) = 73.5 N
8 0
3 years ago
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