The isotopes half life is 2 hours
Since given the following :
time = 8 hours × 3600s/hr = 28800 seconds
A₀ = 80 Bq as the first registration of detector counts per second
A = 5 Bq as the registration of detector counts per second eight hours later
Using the formula:
∴ A = A₀ e^-λt
∴ A/A₀ = e^-λt
∴ ln (A/A₀) = -λt
∴ λ = -ln (A/A₀) /t = ln2 / t_{1/2}
∴ t_{1/2} = -ln2 / ln(A/A₀) (t)
∴ t_{1/2} = -ln2 / ln(5/80) (8 hours) = 2 hours
Answer:
Explanation:
From the question we are told that
Magnitude 1 
Magnitude 1 
Generally the Pythagoras equation for the magnitudes is mathematically given as
Therefore resultant magnitude is
Answer: You could tell if you made an error in your calculations by repeating the steps.
Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.
Explanation:
Answer:
13.524 N
Explanation:
Volume and densities are given as:
ρ1 = 2.6 g/cm³ => 2600 kg/m³ ; V1 = 0.50 L => 0.5 x 10^-3 m³
ρ2 = 1.0 g/cm³ => 1000 kg/m³ ; V2= 0.25 L => 0.25 x 10^-3 m³
ρ3 = 0.7 g/cm³ => 700 kg/m³ ; V3 = 0.4 L => 0.4 x 10^-3 m³
Next is to calculate force exerted on the bottom of the container due to these liquids:
F= ρ1V1g + ρ2 V2 g+ ρ 3 V3g
where ,
ρ= density
V= volume
g= 9.8m/s²
F= g( 2600 x 0.5 x 10^-3 + 1000 x 0.25 x 10^-3 + 700 x 0.4 x 10^-3)
F= 9.8 (1.38)
F= 13.524 N
Therefore, the force on the bottom of the container due to these liquids is 13.524 N
What are the answers?
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