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11Alexandr11 [23.1K]
3 years ago
14

A rectangle always has

Mathematics
1 answer:
Nikitich [7]3 years ago
7 0
The answer your locking for is C it was kind of hard @ first but i did it :]
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IGNOR MY ANSWER I ALSO NEED TO KNOW IF IT'S OPEND OR CLOSED Graph the solution to this inequality on the number line.
Alex777 [14]

Answer:

open circle

Step-by-step explanation:

\leq \geq = closed cirle\\ =open circle

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2 years ago
Use the graphing calculator to locate the solutions of this system of equations: y = x2 + x – 2 y = –x + 1
bonufazy [111]

Answer:

(–3, 4) and (1,0)

Step-by-step explanation:

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PLEASE HELP! WILL GIVE BRAINLIEST
kiruha [24]

Answer:

73

Step-by-step explanation:

Angle JID is supplementary to Angle JIH so:

180- Angle JIH= Angle JID

180-107=73

Angle JID is opposite to Angle AJF(angle x)

Opposite angles are always equal

Angle JID=Angle AJF(x)

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3 years ago
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Divide. Write in simplest form. 10 divided by 1 2/3 ?
adell [148]

Answer: 6

Step-by-step explanation: First rewrite 10 as 10/1 and 1 and 2/3 as 5/3.

Mixed numbers can be changed to improper fractions by multiplying the denominator by the whole number and then adding the numerator. We then put out numerator over our old denominator.

So we have 10/1 ÷ 5/3 or 10/1 × 3/5.

It's important to understand that dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division to multiplication and flip the second fraction.

Now multiplying across the numerators and across the denominators, we have 30/5. Notice however that 30/5 is not in lowest terms so we divide the numerator and the denominator by the greatest common factor of 30 and 5 which is 6 and we end up with 6.

Therefore, 10 ÷ 1 and 2/3 = 6.

8 0
3 years ago
When a bactericide is added to a nutrient broth in which bacteria are​ growing, the bacteria population continues to grow for a​
baherus [9]

Answer:

a)  1296 bacteria per hour

b) 0 bacteria per hour

c) -1296 bacteria per hour

Step-by-step explanation:

We are given the following information in the question:

The size of the population at time t​ is given by:

b(t) = 9^6 + 6^4t-6^3t^2

We differentiate the given function.

Thus, the growth rate is given by:

\displaystyle\frac{db(t)}{dt} = \frac{d}{dt}(9^6 + 6^4t-6^3t^2)\\\\= 6^4-2(6^3)t

a) Growth rates at t = 0 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=0}= 6^4-2(6^3)(0) = 1296\text{ bacteria per hour}

b) Growth rates at t = 3 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=3}= 6^4-2(6^3)(3) = 0\text{ bacteria per hour}

c) Growth rates at t = 6 hours

\displaystyle\frac{db(t)}{dt} \bigg|_{t=6}= 6^4-2(6^3)(6) = -1296\text{ bacteria per hour}

3 0
4 years ago
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