How many hundreds are there in 5000

Mathematics

2 answers:

dimulka [17.4K]2 years ago

8 0

We know that there are ten 100s in 1000 so there must be fifty 100s in 5000.
Hope this helps :)

Mila [183]2 years ago

6 0

The answer is 50
the easy way to find the answer is to take off the two zeros at the end of the number.

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A book has 150 pages, every page is numbered. how many digits are used?

IrinaK [193]

300 digits/numbers are used.

150pages * 2(two sides to one page) = 300numbers

Hope this helps!!!

7 0

2 years ago

Which constant could each equation be multiplied by to eliminate the x variable in this system of equations? 4x + 5y = 62 5x − 3

qwelly [4]

Answer:

Multiply equation $4x+5y=62$ by 5 and $5x-3y=22$ by 4

Step-by-step explanation:

Given:

Equations are $4x+5y=62,5x-3y=22$

To find: constant by which each equation should be multiplied to eliminate the variable $x$ in the given system of equations

Solution:

$4x+5y=62...(i)\\5x-3y=22...(ii)$

Multiply equation (i) by 5 and (ii) by 4 to get the following equations:

$20x+25y=310\\20x-12y=88$

On subtracting these equations, we get

$(20x+25y)-(20x-12y)=310-88\\\\13y=222$

So, the variable $x$ gets eliminated

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2 years ago

FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.

AnnyKZ [126]

Answer:

A) $5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5}$ (Yes. It has a value between zero and one.)

B) $\frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147$ (No. It does not have a value between zero and one.)

C) $\left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}$ . (Yes. It has a value between zero and one.)

D) $\frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49}$ (Yes. It has a value between zero and one.)