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3 years ago

Write the formula for the polyatomic ion in fe(hco3)3. express your answer as an ion.

Chemistry

1 answer:

Juliette [100K]3 years ago

6 0

Ions can be atomic or molecular. If an atom contains either positive or negative charge it said to be atomic cation or atomic anion.

When a molecule carry positive or negative charge it is called as polyatomic cation or polyatomic anion. Generally charged or ionized molecules are called as polyatomic ions.

In given question Fe(HCO₃)₃ ionizes as follow,

Fe(HCO₃)₃ → Fe³⁺ + 3 HCO₃⁻

The Ions produced are Fe³⁺ and HCO₃⁻. Fe³⁺ is said to be atomic (Ferric) ion and HCO₃⁻ (Bicarbonate) is polyatomic ion or molecular ion.

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Hydrogen gas was collected by water displacement. what was pressure of the h2 collected if the temperature was 26°c?

Vedmedyk [2.9K]

The ideal gas law may be written as
$p= \frac{\rho R T}{M}$
where
p = pressure
ρ =density
T = temperature
M = molar mass
R = 8.314 J/(mol-K)

For the given problem,
ρ = 0.09 g/L = 0.09 kg/m³
T = 26°C = 26+273 K = 299 K
M = 1.008 g/mol = 1.008 x 10⁻³ kg/mol

Therefore
$p= \frac{(0.09 \, kg/m^{3})*(8.314 \, J/(mol-K))*(299 \, K)}{1.008 \times 10^{-3} \, kg/mol} =2.2195 \times 10^{5} \, Pa$

Note that 1 atm = 101325 Pa
Therefore
p = 2.2195 x 10⁵ Pa
= 221.95 kPa
= (2.295 x 10⁵)/101325 atm
= 2.19 atm

Answer:
2.2195 x 10⁵ Pa (or 221.95 kPa or 2.19 atm)

4 0

3 years ago

5.4x10^3x1.2 x 10^7 in scientific notation

BartSMP [9]

6.4*10^10 is the answer in scientific notation

5 0

3 years ago

Which of the following would have the largest amount of mass?

Klio2033 [76]

Each of the prefixes means a different thind:
Nano means 0.000000001
Kilo means 1000
Milli means 0.001
Centi means 0.01
Out of these four, the biggest is b: 1 kilogram

5 0

4 years ago

When a -COOH group replaces a hydrogen in a hydrocarbon the result is a/an ____.

jonny [76]

Carboxylic acid...........

7 0

3 years ago

A 60.0 kg object is moving east at 8.00 m/s, and then slows down to 4.00 m/s. How much work was done?

Colt1911 [192]

Answer:

-1440J

Explanation:

Hello,

This question requires us to calculate the work done on a object to move it from point A to point B

Data

Mass = 60kg

Initial velocity (V1) = 8.0m/s

Final velocity (V2) = 4.0m/s

Workdone on an object is equal to force applied on the object to move it through a particular distance.

Work done = force × distance

Force (F) = mass × acceleration

Distance = s

F = Ma

Work done = M× a × s

But a = velocity (v) / time (t)

Work done = mvs / t

But velocity = distance/ time

Work done = mv × v/

Work done = mv²

Work done = ½mv²

Workdone = ½M(V2² - V1²)

Workdone = ½ × 60 (4² - 8²)

Work done = 30 × (16 - 64)

Workdone = 30 × (-48)

Work done = -1440J

Work done = -1.44kJ

The workdone on the object is equal to -1.44kJ

5 0

4 years ago