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Volgvan
3 years ago
7

Write the formula for the polyatomic ion in fe(hco3)3. express your answer as an ion.

Chemistry
1 answer:
Juliette [100K]3 years ago
6 0
Ions can be atomic or molecular. If an atom contains either positive or negative charge it said to be atomic cation or atomic anion.

When a molecule carry positive or negative charge it is called as polyatomic cation or polyatomic anion. Generally charged or ionized molecules are called as polyatomic ions.

In given question Fe(HCO₃)₃ ionizes as follow,

                         Fe(HCO₃)₃    →    Fe³⁺  +  3 HCO₃⁻

The Ions produced are Fe³⁺ and HCO₃⁻. Fe³⁺ is said to be atomic (Ferric) ion and HCO₃⁻ (Bicarbonate) is polyatomic ion or molecular ion.

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1. Electrons surround the nucleus in defined regions called _________________.
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3 years ago
Which of the following has the largest electronegativity? AI, Cu, S, or O?
puteri [66]

Answer:

O(Oxygen)

Explanation:

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7 0
3 years ago
Soda ash (sodium carbonate) is widely used in the manufacture of glass. Prior to the environmental movement much of it was produ
egoroff_w [7]

Answer:

NaCl is the limiting reactant

18.0g of CaCO3 are in excess

113.4g Na2CO3 are produced

118.7g CaCl2 are produced

Explanation:

To solve this question we need to convert the mass of each reactant to moles in order to find the limitng and excess reactant to find the amount of products that would be produced:

<em>Moles CaCO3:</em>

125g * (1mol / 100.09g) = 1.25 moles

<em>Moles NaCl:</em>

125g * (1mol / 58.44g) = 2.14 moles

For a complete reaction of 2.14 moles of NaCl are required:

2.14 moles NaCl * (1mol CaCO3 / 2 mol NaCl) = 1.07 moles of CaCO3.

As there are 1.25 moles, <em>Calcium carbonate is the excess reactant and NaCl the limiting reactant</em>

The moles of CaCO3 in excess are:

1.25mol - 1.07mol = 0.18mol CaCO3 and the mass is:

0.18mol CaCO3 * (100.09g / mol) = 18.0g of CaCO3 are in excess

The moles of Na2CO3 and CaCl2 produced are:

2.14 moles NaCl * (1mol Na2CO3-1mol CaCl2 / 2 mol NaCl) = 1.07 moles are produced.

The masses are:

1.07 mol Na2CO3 * (105.99g / mol) = 113.4g Na2CO3

1.07 mol CaCl2 * (110.98g / mol) = 118.7g CaCl2

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3 years ago
What is a solution?
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