Answer:
P = 14.1 atm
Explanation:
Given data:
Mass of methane = 64 g
pressure exerted by water vapors = ?
Volume of engine = 24.0 L
Temperature = 515 K
Solution:
Chemical equation:
CH₄ + 2O₂ → CO₂ + 2H₂O + energy
Number of moles of methane:
Number of moles = mass / molar mass
number of moles = 64 g/ 16 g/mol
Number of moles = 4 mol
Now we will compare the moles of water vapors and methane.
CH₄ : H₂O
1 : 2
4 : 2/1×4 = 8 mol
Pressure of water vapors:
PV = nRT
R = general gas constant = 0.0821 atm.L/mol.K
P = 8 mol × 0.0821 atm.L/mol.K× 515 K / 24.0 L
P = 338.25 atm.L/ / 24.0 L
P = 14.1 atm
Enthalpy change is the difference between energy used and energy gained. The change in enthalpy of the liquid mercury is 0.0231 kJ.
<h3>What is the enthalpy change?</h3>
Enthalpy change is the difference between the energy used to break chemical bonds and the energy gained by the products formed in a chemical reaction.
The enthalpy change is given by,

and,

Given,
Mass of the liquid mercury (m) = 11.0 gm
The specific heat of mercury (c) = 0.14 J per g per degree Celsius
Temperature change = 15 degrees Celsius
Enthalpy change is calculated as:

Therefore, 0.0231 kJ is the change in enthalpy.
Learn more about enthalpy change here:
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