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sergij07 [2.7K]
3 years ago
6

If you have a gas that starts out with a pressure of 720 mm Hg and a volume of 1500mL, what is the new volume if you increase th

e pressure to 2 atm?
(Gas stoichiometry)
Chemistry
1 answer:
Bad White [126]3 years ago
3 0
 the new  volume   is  calculated by  use  of  Boyles  law   formula

that  is P1V1=p2v2

v2=  p1v1/p2

P1=  720  mmhg
v1=  1500ml
p2 =  2 atm  
V2=?
convert  P2  to  mmhg  =      2  x760=  1520  mmhg

V2=   720mmhg  x1500  ml/  1520mmhg  =  710.53  ml
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3 years ago
Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?
german

Answer : The correct option is, (A) AlCl_3

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) AlCl_3

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of AlCl_3 will be,

AlCl_3\rightarrow Al^{3+}+3Cl^{-}

So, Van't Hoff factor = Number of solute particles = Al^{3+}+3Cl^{-} = 1 + 3 = 4

(B) KI

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of KI will be,

KI\rightarrow K^{+}+I^{-}

So, Van't Hoff factor = Number of solute particles = K^{+}+I^{-} = 1 + 1 = 2

(C) CaCl_2

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^{-}

So, Van't Hoff factor = Number of solute particles = Ca^{2+}+2Cl^{-} = 1 + 2 = 3

(D) MgSO_4

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of MgSO_4 will be,

MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}

So, Van't Hoff factor = Number of solute particles = Mg^{2+}+SO_4^{2-} = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, AlCl_3

7 0
3 years ago
What is the approximate value of the ccc bond angle in ch3ch2ch2oh
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Answer:

The value of the carbon bond angles are 109.5 °

Explanation:

CH3CH2CH2OH = propanol . This is an alcohol.

All bonds here are single bonds.

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Sp3- types have angles of 109.5 ° between the carbon - atoms.

This means that the value of the carbon bond angles are 109.5 °

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