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lesya692 [45]
4 years ago
5

Given that the boiling points of ethanol and diethyl ether are 78.1°C and 34.6°C, respectively, which should have the higher vap

or pressure at 20.0°C?
Chemistry
2 answers:
anyanavicka [17]4 years ago
7 0
Diethyl ether, since 20 is closer to 34.6 it should start boiling faster than the other which is no where near it
max2010maxim [7]4 years ago
6 0

Answer:- Diethyl ether would have higher vapor pressure at 20.0 degree C.

Explanations:- Boiling point is the temperature at which the vapor pressure equals to the atmospheric pressure.

Looking at the given vapor pressure values, ethanol needs to be heat up at 78.1 degree C to makes it's vapor pressure equals to atmospheric pressure where as diethyl ether only needs to be heat up at 34.6 degree C.

Hence, lower is the boiling point, higher is the vapor pressure.

Now, 20.0 degree C is more closer to 34.6 degree C . it means the temperature difference is less for diethyl ether as compared to ethanol.

So, as the boiling point of diethyl ether is low, the vapor pressure of it would be higher at 20.0 degree C.

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If 0.138g of cyclohexene (c6h10) was obtained from 0.240g of cyclohexanol (c6h120), what is the percentage yield of cyclohexene?
tino4ka555 [31]
<span>Given in the question- 1 mole of cyclohexanol = > 1 mole of cyclohexene Molar mass 100.16 g/mol moles of cyclohexanol = .240 / 100.16= 0.002396 moles Molar mass 82.143 g/mol moles of cyclohexene formed @100 % yield = 0.002396 Molar mass 82.143 g/mol mass of cyclohexene @ 100 % = .002396 x 82.143 = 0.197g bur we have .138g so % yield = .138 / .197 = 70.0 % Ans- 70 percentage yield of cyclohexene.</span>
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4 years ago
If you were to add a proton to a neutral atom what would change
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8 0
3 years ago
A sample of nitrogen gas with a volume of 180 cm at a temperature of
maksim [4K]

Answer:

The final pressure of gas is 82.64 KNm⁻²

Explanation:

Given data:

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Temperature of gas = 27°C

Initial pressure = 101 KNm⁻²

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Solution:

The given problem will be solved through the Boly's law,

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Mathematical expression:

P₁V₁ = P₂V₂

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P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

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3 years ago
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Answer:

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When an experiment is done more than once to determine if the results are statistically ok, two forms of the validations are possible the accuracy and precision. When the values of the various experiments are close to the known value, then they are accurate. When the values are close to each other they are precise. So, sometimes the results are precise but are not accurate, and vice-versa.

a) Here, the person wants to find if the 5 aliquots will have close results, so, he or she is looking for precision.

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