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lesya692 [45]
4 years ago
5

Given that the boiling points of ethanol and diethyl ether are 78.1°C and 34.6°C, respectively, which should have the higher vap

or pressure at 20.0°C?
Chemistry
2 answers:
anyanavicka [17]4 years ago
7 0
Diethyl ether, since 20 is closer to 34.6 it should start boiling faster than the other which is no where near it
max2010maxim [7]4 years ago
6 0

Answer:- Diethyl ether would have higher vapor pressure at 20.0 degree C.

Explanations:- Boiling point is the temperature at which the vapor pressure equals to the atmospheric pressure.

Looking at the given vapor pressure values, ethanol needs to be heat up at 78.1 degree C to makes it's vapor pressure equals to atmospheric pressure where as diethyl ether only needs to be heat up at 34.6 degree C.

Hence, lower is the boiling point, higher is the vapor pressure.

Now, 20.0 degree C is more closer to 34.6 degree C . it means the temperature difference is less for diethyl ether as compared to ethanol.

So, as the boiling point of diethyl ether is low, the vapor pressure of it would be higher at 20.0 degree C.

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What effect will increasing temperature have on equilibrium?
professor190 [17]
Depends if the reaction is endo or exo thermic

Endothermic reaction
Increasing the temperature will shift the equilibrium to the right-hand side of the equilibrium. to oppose the change in temperature.


Exothermic reaction
Increasing the temperature will shift the equilibrium to the left-hand side of the equilibrium. to oppose the change in temperature.

Hope that helps 
4 0
3 years ago
What is the frequency of an electromagnetic wave that has a wavelength of
AlexFokin [52]

Answer:

D. 2.5 x 10 ^-14 Hz

Explanation:

Use wavelength formula: v = f x wavelength

Rearrange formula for frequency.

f = wavelength / v

f = 7.6 x 10 ^-6 / 3.00 x 10 ^8

f = 2.5 x 10^-14 Hz

3 0
3 years ago
The pot shown in the picture is made of two different metals. Why is the handle made of a different metal than the rest of the p
sertanlavr [38]
The rest of the bot needs to be able to heat up to cook ur food but the handles should be cooler so u can touch them
8 0
4 years ago
Read 2 more answers
Determine each type of reaction. 2 C 2 H 2 ( g ) + 5 O 2 ( g ) ⟶ 4 C O 2 ( g ) + 2 H 2 O ( l ) 2CX2HX2(g)+5OX2(g)⟶4COX2(g)+2HX2O
Valentin [98]

Answer:

2 C 2 H 2 ( g ) + 5 O 2 ( g ) ⟶ 4 C O 2 ( g ) + 2 H 2 O ( l )- combustion reaction

N H 4 N O 3 ( s ) ⟶ N 2 O ( g ) + 2 H 2 O ( l )- decomposition reaction

C O ( g ) + 2 H 2 ( g ) ⟶ C H 3 O H ( l ) - combination reaction

2 F e ( s ) + 6 H C l ( a q ) ⟶ 2 F e C l 3 ( a q ) + 3 H 2 ( g )- Redox reaction

C a C l 2 ( a q ) + N a 2 C O 3 ( a q ) ⟶ 2 N a C l ( a q ) + C a C O 3 ( s )- double displacement reaction

Explanation:

We can determine the type of reaction by considering the reactants and products.

Combustion is a reaction between a substance and oxygen which produces heat and light. The first reaction is the equation for the combustion of ethyne.

A decomposition reaction is one in which a single reactant breaks down to form products. The second reaction is the decomposition of ammonium nitrate.

A  combination reaction is said to occur when two elements or compounds react to form a single product. The third reaction is the combination of carbon dioxide and methane to form  methanol.

An oxidation-reduction reaction is a reaction in which there is a change in oxidation number of species from left to right of the chemical reaction equation. The fourth reaction is the oxidation of iron (0 to +3 state) and reduction of hydrogen (+1 to 0 state).

A double displacement reaction is a reaction in which ions exchange partners from left to right in the reaction equation. The fifth reaction is a double displacement reaction. Both Na^+ and Ca^2+ exchanged partners from left to right of the reaction equation.

4 0
4 years ago
When 25.0 ml of 0.500 m h2so4 is added to 25.0 ml of 1.00 m koh in a coffee-cup calorimeter at 23.50°c, the temperature rises to
AlladinOne [14]

The chemical reaction that occurs between the given substances is a neutralization reaction as shown below :

 

H_2SO_4 + 2KOH -> K_2SO_4 + 2H_2O

<span>1 mol            2 mol      1 mol           2 mol </span>

 

<span>The number of moles of the given substances  is calculated as shown : </span>

Number of moles of H_2SO_4 = 25.0 mL x 0.50 M = 12.5 millimoles

Number of moles of KOH = 25.0 mL x 1.00 M = 25.0 millimoles

 

As 1 mol of sulfuric acid reacts with 2 mol of KOH to give 2 mol of water, 12.5 millimoles of sulfuric acid completely reacts with 25.0 millimoles of KOH to give 25.0 millimoles of water.

Total volume of the solution = 25.0 mL + 25.0 mL = 50.0 mL.

Density of water is 1 g/mL. Use this to calculate the mass of the solution.

<span>Mass of the solution – 50.0 mL x 1 g/mL = 50.0  </span>

The specific heat of water is 4.184 J/gK. The temperature of the solution is increased from 23.5 degrees Celsius to 30.17 degrees Celsius.

The amount of heat released = 4.184 J/gK x 50.0 g x (30.17C – 23.50C) 1395 J

 

The amount of heat released per one mole of water formed can be calculated as shown :

The amount of heat released for formation of mole water = 1395 J / (25.0 m mol x 1mol/1000 m mol)

= 55,800 J

<span> </span>

8 0
3 years ago
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