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ser-zykov [4K]
3 years ago
10

Can any one help me solve this ?

Mathematics
1 answer:
Lana71 [14]3 years ago
3 0

Step 1. Take out the constants

(4 * 7)xx^2

Step 2. Simplify 4 * 7 to 28

28xx^2

Step 3. Use the Product Rule

28x^1 + 2

Step 4. Simplify 1 + 2 to 3

28x^3

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I need help with this please
SpyIntel [72]

Answer:

n= -1.2

Step-by-step explanation:

I think because if you use slope equation to find the slope which is 3/5 and then you use point slop equation to find out what the equation would be. y=3/5x and then you substitue y for 18 and solve/simplify the equation to get -1.2.

4 0
3 years ago
CORRECT ANSWER GETS BRAINLIEST
MissTica

Pretty sure it's D :)))))

5 0
4 years ago
Read 2 more answers
Geometry - Law of Sines question #17. Please help, I am stuck.
Flauer [41]

By the law of sines, m∠<em>EFG</em> is such that

sin(m∠<em>EFG</em>) / (8 in.) = sin(m∠<em>G</em>) / (7.5 in)

so you need to find m∠<em>G</em>.

The interior angles to any triangle sum to 180°, so

m∠<em>DEG</em> = m∠<em>D</em> + m∠<em>G</em> + 43°

m∠<em>DEG</em> + m∠<em>D</em> + m∠<em>G </em>= 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°

180° = 2 (m∠<em>D</em> + m∠<em>G</em>) + 43°

137° = 2 (m∠<em>D</em> + m∠<em>G</em>)

68.5° = m∠<em>D</em> + m∠<em>G</em>

But ∆<em>DEG</em> is isosceles, so m∠<em>D</em> = m∠<em>G</em>, which means

68.5° = 2 m∠<em>G</em>

34.25° = m∠<em>G</em>

<em />

Then

sin(m∠<em>EFG</em>) = (8 in.) sin(34.25°) / (7.5 in)

m∠<em>EFG</em> ≈ sin⁻¹(0.600325) ≈ 36.8932°

4 0
3 years ago
The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below. See Attached Excel for Data. Assume t
motikmotik

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The amounts (in ounces) of randomly selected eight 16-ounce beverage cans are given below.

16.5, 15.2, 15.4, 15.1, 15.3, 15.4, 16, 15.1

Assume that the amount of beverage in a randomly selected 16-ounce beverage can has a normal distribution. Compute a 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans and fill in the blanks appropriately.

A 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is ( , ) ounces. (round to 3 decimal places)

Answer:

99\% \: \text {confidence interval} = (14.886, \: 16.113)\\\\

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

Step-by-step explanation:

Let us find out the mean amount of the 16-ounce beverage cans from the given data.

Using Excel,

=AVERAGE(number1, number2,....)

The mean is found to be

\bar{x} = 15.5

Let us find out the standard deviation of the 16-ounce beverage cans from the given data.

Using Excel,

=STDEV(number1, number2,....)

The standard deviation is found to be

$ s = 0.4957 $

The confidence interval is given by

\text {confidence interval} = \bar{x} \pm MoE\\\\

Where \bar{x} is the sample mean and Margin of error is given by

$ MoE = t_{\alpha/2} \cdot (\frac{s}{\sqrt{n} } ) $ \\\\

Where n is the sample size, s is the sample standard deviation and  is the t-score corresponding to a 99% confidence level.

The t-score corresponding to a 99% confidence level is

Significance level = α = 1 - 0.99 = 0.01/2 = 0.005

Degree of freedom = n - 1 = 8 - 1 = 7

From the t-table at α = 0.005 and DoF = 7

t-score = 3.4994

MoE = t_{\alpha/2}\cdot (\frac{s}{\sqrt{n} } ) \\\\MoE = 3.4994 \cdot \frac{0.4957}{\sqrt{8} } \\\\MoE = 3.4994\cdot 0.1753\\\\MoE = 0.6134\\\\

So the required 99% confidence interval is

\text {confidence interval} = \bar{x} \pm MoE\\\\\text {confidence interval} = 15.5 \pm 0.6134\\\\\text {confidence interval} = 15.5 - 0.6134, \: 15.5 + 0.6134\\\\\text {confidence interval} = (14.886, \: 16.113)\\\\

Therefore, the 99% confidence interval for the population mean amount of beverage in 16-ounce beverage cans is (14.886, 16.113) ounces.

8 0
4 years ago
Determine whether the random variable is discrete or continuous. In each​ case, state the possible values of the random variable
Deffense [45]

Answer:

C. The random variable is discrete. The possible values are x= 0, 1, 2... 100

C. The random variable is continuous. The possible values are a > 0.

Step-by-step explanation:

Here is the complete question :

Determine whether the random, variable is discrete or continuous.

In each case, state the possible values of the random variable.

(a) The number of people in a restaurant that has a capacity of 100

(b) The square footage of a house.

(a) Is the number of people in a restaurant that has a capacity of 100 discrete or continuous?

A. The random variable is discrete. The possible values are 0≤x≤ 100.

B. The random variable is continuous. The possible values are 0≤x≤ 100.  

C. The random variable is discrete. The possible values are x= 0, 1, 2... 100

D. The random variable is continuous. The possible values are x= 0, 1, 2... 100

b) Is the square footage of a house discrete or continuous?

A. The random variable is discrete. the possible values are a > 0  

B. The random variable is discrete. The possible values are a = 1, 2, 3...

C. The random variable is continuous. The possible values are a > 0.

D. The random variable is continuous. The possible values are a = 1,2, 3,

A discrete variable is a variable that can be counted. It has a finite amount of values. The number of people in the restaurant is finite. It cannot exceed 100. At any point in time when you count the number of people in the restaurant and it would be between 0 - 100

A continuous variable has an infinite amount of values it can take on. The square footage of a house can be of any size. there is no limit to the size of a house. it can be as small or big as the architect's imagination allows.

8 0
3 years ago
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