Answer:
y = 9.64 m
Explanation:
This exercise should be solved using kinematics in one dimension, let's write the equations for the two cases presented
The rock is released
y = y₀ + V₀₁ t₁ - ½ g t₁²
In this case the speed starts is zero
y = y₀ - ½ g t₁²
The rock is thrown up
y = y₀ + v₀² t₂ -½ g t₂²
The height that reaches the floor is zero
y₀ - ½ g t₁² = y₀ + v₀₂ t₂ - ½ g t₂²
We use the initial velocity with the equation
v₂² = v₀₂² - 2 g y
At the point of maximum height v₂ = 0
v₀₂ = √ (2 g 
)
g (-t₁² + t₂²) = 2 √ (2 g ) t₂²
g (- 4.15² + 6.30²) = 2 √ (2 2 g) 6.3
g (22.4675) = 25.2 √ g
g² = 2²5.2 / 22.4675 g
g = 1.12 m / s²
Having the value of g we can use any equation to find the height
y = ½ g t₁²
y = ½ 1.12 4.15²
y = 9.64 m
To calculate for the pressure of the system, we need an equation that would relate the
number of moles (n), pressure (P), and temperature (T) with volume (V). There are a number of equations that would relate these values however most are very complex equations. For
simplification, we assume the gas is an ideal gas. So, we use PV = nRT.<span>
PV = nRT where R is the universal gas
constant
P = nRT / V</span>
<span>P = 3.40 mol ( 0.08205 L-atm / mol-K ) (251 + 273.15 K) / 1.75 L </span>
<span>P = 83.56 atm</span>
<span>
</span>
<span>Therefore, the pressure of the gas at the given conditions of volume and temperature would be 83.56.</span>
Light travels at a speed of:
The distance between Mercury and Sun is
, so the time it takes is
if we want to convert this into minutes, keeping in mind that 1 min = 60 seconds, we should divide this value by 60:
