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2 years ago

Please help with this question. Will give 5 stars and a thanks. Thanks!

Mathematics

1 answer:

EleoNora [17]2 years ago

3 0

Answer: the height of the flagpole is 21 ft.

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I really need help. I'm failing this class guys

Aleonysh [2.5K]

17. $2u +5.2 \leq 9.4 + u \\2u - u \leq 9.4 -5.2\\u \leq 4.2$

18. $3(f+2) > 2f + 4\\3f + 6 > 2f + 4 \\3f-2f > 4-6\\f > -2\\$ The answer is I.

19. $4 < 6b -2 \leq 28\\4+2 < 6b \leq 28+2\\6 < 6b \leq 30\\6/6 < b \leq 30/6\\1 < b \leq 5$

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3 years ago

Which decimal is equivalent to -3 1/8?

ryzh [129]

Answer:

-3.125

Step-by-step explanation:

7 0

3 years ago

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Which statement could be used in step 2 when proving x =

Marianna [84]

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i really know like omg please give brainlest

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3 years ago

Hey! Can someone check my answers?

Andrew [12]

The greatest common factor is the biggest number taken from the values.

Q1. The answer is <span>A. 5y^6
</span>
$20 y^{9} +5 y^{6}= 4*5 y^{9}+5 y^{6}$
Since $x^{a}* x^{b} =x^{a+b}$ , then $x^{9}= x^{3}* x^{6}$

Back to our expression:
$4*5 y^{9}+5 y^{6}=4*5 y^{3}*y^{6}+5 y^{6}=4 y^{3}*5y ^{6}+ 5y ^{6}*1=5 y^{6} (4y ^{3} +1)$
The greatest common factor is thus $5 y^{6}$

Q2. The answer is <span>D. 12xy^2
</span>
$12x y^{5}+60 x^{4} y^{2} -24 x^{3} y^{3}=12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}$
We will use the rule $x^{a}* x^{b} =x^{a+b}$ to factorise the exponents:
$12x y^{5}+5*12 x^{4} y^{2} -2*12 x^{3} y^{3}= \\ =12x*y^{2}*y^{3}+5*12*x* x^{3} *y^{2}-2*12x* x^{2} *y*y^{2}= \\ =12xy^{2}*y^{3}+12xy^{2}*5 x^{3} -12xy^{2}*2 x^{2} y= \\ =12xy^{2}(y^{3}+5 x^{3}-2 x^{2} y)$
The greatest common factor is thus $12xy^{2}$

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3 years ago

If y is directly proportional to x and y = 17.5 when x=21 find y when x=39

morpeh [17]

direct proportion y=kx , k is constant and k does not equal to 0.

17.5=k(21)

k=5/6

when x =39

y=5/6 ×39

y=32.5

4 0

3 years ago

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