2 and 1/2 hours is 2 hours and 30 minutes
So
1145+230=13:75 (3:15 is your answer)
The measure of ∠BAF is 54°.
Solution:
DF and CE are intersecting lines.
m∠EAF = 72° and AB bisects ∠CAF.
∠EAF and ∠DAC are vertically opposite angles.
Vertical angle theorem:
<em>If two lines are intersecting, then vertically opposite angles are congruent.</em>
∠DAC ≅ ∠EAF
m∠DAC = 72°
<em>Sum of the adjacent angles in a straight line = 180°</em>
m∠DAE + m∠EAF = 180°
m∠DAE + 72° = 180°
Subtract 72° from both sides.
m∠DAE = 108°
∠CAF and ∠DAE are vertically opposite angles.
⇒ m∠CAF = m∠DAE
⇒ m∠CAF = 108°
AB bisects ∠CAF means ∠CAB = ∠BAF
m∠CAB + m∠BAF = 108°
m∠BAF + m∠BAF = 108°
2 m∠BAF = 108°
Divide by 2 on both sides, we get
m∠BAF = 54°
Hence the measure of ∠BAF is 54°.
First solve the length of side BC, CD, EF and FA
Since BC = CD = sqrt( 10^2 + 10^2)
BC = CD = 14.1421
FA = EF = sqrt(10^2 + 20^2)
= 23.3607
So the perimeter = 10 + 10 + 14.1421 + 14.1421 + 23.3607
= 93
The area is made up be triangle FAE, rectangle ABDE and
triangle BCD
A = 0.5(20)(20) + (10)(20) + 0.5(20)(10)
<span>A = 500 sq units</span>
Answer:
Angles RSQ and WVX are alternate interior angles.
Hope this helps!
The isosceles triangle is missing so i have attached it.
Answer:
Length of unknown side = 5p + 6
Step-by-step explanation:
In isosceles triangle, two of the sides are equal. In the attached triangle, we see that one of the equal sides is given as 5p + 3.
Thus,the second equal side is also 5p + 3.
Now, perimeter of a triangle is the sum of the three sides.
We have two sides and let the third side be denoted as x.
Thus;
Perimeter = (5p + 3) + (5p + 3) + x
We are given perimeter = 15p + 12
Thus;
(5p + 3) + (5p + 3) + x = 15p + 12
10p + 6 + x = 15p + 12
Rearranging, we have;
x = 15p - 10p + 12 - 6
x = 5p + 6
