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Ivenika [448]
3 years ago
10

I need help finishing this.

Mathematics
1 answer:
tekilochka [14]3 years ago
3 0

Answer:

3x³

Step-by-step explanation:

(81x¹² / 3x³)^⅓

(27x⁹)^⅓

You got a good start.  To finish, rewrite 27 as 3³, then multiply the exponents of each factor by ⅓.

(3³ x⁹)^⅓

3x³

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3x3-27x=0<br> Solve by factoring a
Eddi Din [679]

After factoring 3x^3-27x=0 the solutions are x=0 , x=3, x= -3

Step-by-step explanation:

We need to solve by factoring:

3x^3-27x=0

Solving:

3x^3-27x=0

Taking 3x common:

3x(x^2-9)=0

Now using formula a^2-b^2=(a-b)(a+b)

3x((x)^2-(3)^2)=0\\3x(x-3)(x+3)=0

3x=0\,\,and\,\,x+3=0\,\,and\,\,x-3=0\\x=0\,\,and\,\,x=-3\,\,and\,\,x=3\\

So, After factoring 3x^3-27x=0 the solutions are x=0 , x=3, x= -3

Keywords: Factorization

Learn more about Factorization at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256
  • brainly.com/question/1414350

#learnwithBrainly

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3 years ago
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Answer:

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