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iragen [17]
3 years ago
5

When butane burns in oxygen, it produces carbon dioxide and water. This reaction is represented in this equation:

Chemistry
2 answers:
Shtirlitz [24]3 years ago
6 0

<u>Answer:</u> In the given equation, there are 8 atoms of carbon, 26 atoms of oxygen and 20 atoms of hydrogen on each side of the equation.

<u>Explanation:</u>

Law of conservation of mass states that mass can neither be created nor be destroyed but it can only be transformed from one form to another form.

This also means that total mass on the reactant side must be equal to the total mass on the product side.

For the given chemical reaction:

2C_4H_{10}+13O_2\rightarrow 8CO_2+10H_2O

<u>On reactant side:</u>

Number of carbon atoms = 8

Number of hydrogen atoms = 20

Number of oxygen atoms = 26

<u>On product side:</u>

Number of carbon atoms = 8

Number of hydrogen atoms = 20

Number of oxygen atoms = 26

Hence, in the given equation, there are 8 atoms of carbon, 26 atoms of oxygen and 20 atoms of hydrogen on each side of the equation.

Vadim26 [7]3 years ago
5 0
The answer fam is.............This equation is balanced because there are 8 atoms of carbon (C), 26 atoms of oxygen (O), and 20 atoms of hydrogen (H) on each side of the equation.
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Answer:

Sulphuric acid is the on

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3 0
2 years ago
If 120.3 mL of water is shaken with oxygen gas at 2.1 atm, it will dissolve 0.0043 g O2. Estimate the Henry's law constant for t
nikklg [1K]

<u>Answer:</u> The Henry's law constant for oxygen gas in water is 1.702\times 10^{-5}g/mL.atm

<u>Explanation:</u>

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{O_2}=K_H\times p_{O_2}

where,

K_H = Henry's constant = ?

C_{O_2} = solubility of oxygen gas = 0.0043g/120.3mL

p_{O_2 = partial pressure of oxygen gas = 2.1 atm

Putting values in above equation, we get:

0.0043g/120.3mL=K_H\times 2.1atm\\\\K_H=\frac{0.0043g}{120.3mL\times 2.1atm}=1.702\times 10^{-5}g/mL.atm

Hence, the Henry's law constant for oxygen gas in water is 1.702\times 10^{-5}g/mL.atm

7 0
2 years ago
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ladessa [460]

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7 0
3 years ago
A large balloon contains 5400 m3 of He gas that is kept at a temperature of 280 K and an absolute pressure of 1.10 x 105 Pa. Fin
patriot [66]

Answer:

1.02 × 10⁶ g

Explanation:

Step 1: Given data

  • Volume of the balloon (V): 5400 m³
  • Temperature (T): 280 K
  • Absolute pressure (P): 1.10 × 10⁵ Pa
  • Molar mass of He (M): 4.002 g/mol

Step 2: Convert "V" to L

We will use the conversion factor 1 m³ = 1000 L.

5400 m³ × 1000 L/1 m³ = 5.400 × 10⁶ L

Step 3: Convert "P" to atm

We will use the conversion factor 1 atm = 101325 Pa.

1.10 × 10⁵ Pa × 1 atm / 101325 Pa = 1.09 atm

Step 4: Calculate the moles of He (n)

We will use the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 1.09 atm × 5.400 × 10⁶ L / 0.08206 atm.L/mol.K × 280 K

n = 2.56 × 10⁵ mol

Step 5: Calculate the mass of He (m)

We will use the following expression.

m = n × M

m = 2.56 × 10⁵ mol × 4.002 g/mol

m = 1.02 × 10⁶ g

8 0
2 years ago
Sugar cannot be separated from sugar solution by filtering explain why?​
alexdok [17]

Answer:

The sugar particles are so small that they have dissolved in the water, and can easily pass through the filter.

5 0
2 years ago
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