Question

In Part B the given conditions were 1.00 mol of argon in a 0.500-L container at 18.0°C. You identified that the ideal pressure (P ) was 47.8 atm, and the real pressure (Prral) was 45.7 atm under these conditions. Complete the sentences to analyze this difference Match the words and compounds in the left column to the appropriate blanks in the sentences on the right. Make certain each sentence is complete before submitting your answer. View Available Hint(s) Reset Help strong intermolecular forces The percent difference between the ideal and real gas is decrease This difference is considered significant, and is best explained because argon atoms have relatively small molecular volumes If the volume of the container were increased to 2.00 L, you would expect the percent difference between the ideal and real gas to 4.38% 4.48% 4.58% increase weak intermolecular forces large molecular volumes

Answer 1

Answer:

4,38%

small molecular volumes

Decrease

Explanation:

The percent difference between the ideal and real gas is:

(47,8atm - 45,7 atm) / 47,8 atm × 100 = 4,39% ≈ 4,38%

This difference is considered significant, and is best explained because argon atoms have relatively small molecular volumes. That produce an increasing in intermolecular forces deviating the system of ideal gas behavior.

Therefore, an increasing in volume will produce an ideal gas behavior. Thus:

If the volume of the container were increased to 2.00 L, you would expect the percent difference between the ideal and real gas to decrease

I hope it helps!