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3 years ago

8

what is the force between two small charged spheres that have charges 2x10(power -7)c and 3x10(power -7)c and are placed 30 cm a

part in air?

1 answer:

Andre45 [30]3 years ago

6 0

F=1/(4*pi*e0)*q1*q2/r^2
e0 ≈ 8,854187817·10^−12
F=1/(4*pi* 8,854*10^(-12))*2*10^(-7)*2*10^(-7)/(0,3)^2 H = <span> 0,003995 </span>H ~ 0,004 H

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Explanation:

Given:

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velocity of the ball after being kicked, $v=18 m.s^{-1}$

mass of the ball, $m=0.425\, kg$

time of application of force, $t=5.3\times 10^{-2}\,s$

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$\Delta p=0.425\times 18$

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$\Delta p_y= 7.65\times sin 30^{\circ}$

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also, impulse

$I=F\times t$ .........................(2)

where F is the force applied for t time.

Then from eq. (1) & (2)

$F\times t=m.v$

$F\times 5.3\times 10^{-2}= 7.65$

$F=144.3396\,N$

Now, the components

$F_x=144.3396\times cos 30^{\circ}$

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&

$F_y=144.3396\times sin 30^{\circ}$

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3 years ago