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3 years ago

PLEASE HELP!!! Will give brainliest!

2 answers:

8 0

The answer is B, Both can be characterized by amplitude, frequency, and wavelength. the speed of both is affected by the medium through which it travels.

Natali5045456 [20]3 years ago

3 0

The correct answer to the question will be B) Both can be characterized by amplitude, frequency, and wavelength. The speed of both is affected by the medium through which it travels.

EXPLANATION:

Light is an electromagnetic wave which is transverse in nature. It contains both the electric field and magnetic field which are perpendicular to each other as well as perpendicular to the direction of propagation.

We know that a transverse wave is characterized by its amplitude, frequency and wavelength . Here, crests and troughs are created which give the idea about the wavelength . The distance between two successive crests or troughs is called wavelength.

A sound wave is a longitudinal wave which moves in the form of compressions and rarefactions. Compressions are the high pressure zones while rarefactions are the low pressure zones in the wave. Here, the distance between two successive compresions or rarefactions is called wavelength of the wave. It is also characterized by frequency and amplitude.

The speed of light is medium dependent . It is more in optically rarer medium while less in optically denser medium . The light does not require any medium for its propagation. It may propagate through space where it has the maximum velocity.

The speed of sound is also medium dependent . It depends on the density and elasticity of the medium.It can not travel through vacuum. It needs a medium for its propagation.

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Before the student releases the cart by cutting the tinsel string, what forces are acting on the cart?

Naya [18.7K]

Answer: TENSION and WEIGHT

Explanation:

Force experienced by the spring is called TENSION while the WEIGHT is the gravitational pull on the body towards the earth surface. Therefore the forces acting on the cart are TENSION and WEIGHT(weight acts downwards (along negative y-axis) while the TENSION upward(along positive y-axis).

5 0

3 years ago

Check all that apply. The magnetic force on the current-carrying wire is strongest when the current is parallel to the magnetic

dedylja [7]

Answer:

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field.

The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current.

The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines.

Explanation:

The magnitude of the magnetic force exerted on a current-carrying wire due to a magnetic field is given by

$F=ILB sin \theta$ (1)

where I is the current, L the length of the wire, B the strength of the magnetic field, $\theta$ the angle between the direction of the field and the direction of the current.

Also, B, I and F in the formula are all perpendicular to each other. (2)

According to eq.(1), we see that the statement:

"The magnetic force on the current-carrying wire is strongest when the current is perpendicular to the magnetic field lines."

is correct, because when the current is perpendicular to the magnetic field, $\theta=90^{\circ}, sin \theta = 1$ and the force is maximum.

Moreover, according to (2), we also see that the statements

"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the field. "

"The direction of the magnetic force acting on a current-carrying wire in a uniform magnetic field is perpendicular to the direction of the current. "

because F (the force) is perpendicular to both the magnetic field and the current.

5 0

3 years ago

The electric field at the surface of a charged, solid, copper sphere with radius 0.220 mm is 4200 N/CN/C, directed toward the ce

NISA [10]

Answer:

The potential at the center of the sphere is -924 V

Explanation:

Given;

radius of the sphere, R = 0.22 m

electric field at the surface of the sphere, E = 4200 N/C

Since the electric field is directed towards the center of the sphere, the charge is negative.

The Potential is the same at every point in the sphere, and it is given as;

$V = \frac{1}{4 \pi \epsilon_o} \frac{q}{R}$ -------equation (1)

The electric field on the sphere is also given as;

$E = \frac{1}{4 \pi \epsilon _o} \frac{|q|}{R^2}$

$|q |= 4 \pi \epsilon _o} R^2E$

Substitute in the value of q in equation (1)

$V = \frac{1}{4 \pi \epsilon_o} \frac{-(4 \pi \epsilon _o R^2E)}{R} \ \ \ \ q \ is \ negative\ because \ E \ is\ directed \ toward \ the \ center\\\\V = -RE\\\\V = -(0.22* 4200)\\\\V = -924 \ V$

Therefore, the potential at the center of the sphere is -924 V

8 0

3 years ago

The red light emitted by a helium–neon laser has a wavelength of 632.8 nm. What is the frequency of the light waves?

Monica [59]

f = 4.74 × 10 ^14 Hz

hope this helps:)

5 0

3 years ago

In regard to the Compton scattering experiment with x-rays incident upon a carbon block, as the scattering angle becomes larger,

BartSMP [9]

Answer:

Increases

Explanation:

In the Compton scattering experiment with x-rays,

The change in operation

$\Delta \lambda = \frac{h}{m_oc} [1-cos\theta]$

Now rest being constant, as \theta increases, cos\theta decreases

Hence, The change in wavelength will increase with the increase in \theta.

Hence, wavelength increases with an increase in the angle of scatttering.

6 0

3 years ago