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Nikitich [7]
3 years ago
5

PLEASE HELP!!! Will give brainliest!

Physics
2 answers:
Contact [7]3 years ago
8 0

The answer is B, Both can be characterized by amplitude, frequency, and wavelength. the speed of both is affected by the medium through which it travels.


Natali5045456 [20]3 years ago
3 0

The correct answer to the question will be B) Both can be characterized by amplitude, frequency, and wavelength. The speed of both is affected by the medium through which it travels.

EXPLANATION:

Light is an electromagnetic wave which is transverse in nature. It contains both the electric field and magnetic field which are perpendicular to each other as well as perpendicular to the direction of propagation.

We know that a transverse wave is characterized by its amplitude, frequency and wavelength . Here, crests and troughs are created which give the idea about the wavelength . The distance between two successive crests or troughs is called wavelength.

A sound wave is a longitudinal wave which moves in the form of compressions and rarefactions. Compressions are the high pressure zones while rarefactions are the low pressure zones in the wave. Here, the distance between two successive compresions or rarefactions is called wavelength of the wave. It is also characterized by frequency and amplitude.

The speed of light is medium dependent . It is more in optically rarer medium while less in optically denser medium . The light does not  require any medium for its propagation. It may propagate through space where it has the maximum velocity.

The speed of sound is also medium dependent . It depends on the density and elasticity of the medium.It can not travel through vacuum. It needs a medium for its propagation.

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What does the inverse square law state?
Dmitry [639]

The Inverse Square Law applies to Radiation. It states that the intensity of any radiation source is inversely proportional to the square of the distance from the source.

I would rather call it “an inverse square law”. Some things vary inversely as the square of something (usually distance) and some things don’t.

For instance, the quantity of light energy per second falling on a tiny area* is inversely related to the square of the distance from the source if a point light source emits light uniformly in all directions. The energy per second will decrease by four times with every twofold increase in distance for a certain area, and nine times with every threefold increase in distance. (Ideally, the area should be a sphere centered on the point source to make the distance clear; nonetheless, an approximate solution is a tiny plane area perpendicular to the line from the point source.) Therefore, light obeys the inverse square law (at least in Euclidean space).

The gravitational and electrical forces are some examples of entities that adhere to the inverse square law. On the other hand, gravitational and electrical potentials adhere to an inverse rule, whereby the potential must be reduced by a factor of two times the distance.

Thank you,

Eddie

8 0
2 years ago
What is the maximum speed at which a car can safely travel around a circular track of radius 55.0 m If the coefficient of fricti
Stella [2.4K]

Answer:

The maximum speed of the car should be 13.7 m/s

Explanation:

For the car to travel at a maximum safe speed , the frictional force acting should be maximum and at the same time should provide the necessary centripetal force.

Let 'k' (=0.3502) be the coefficient of friction and 'N' be the normal force acting on the surface.

Then ,

N = mg , where 'm' is the mass of the body and 'g'(=9.8) is the acceleration due to gravity.

∴ Maximum frictional force , f = kN = kmg

Centripetal force that should act on the car to move with maximum possible speed is -

F = \frac{mv^{2} }{r}  , where 'v' is the velocity of the car and 'r'(=55m) is the radius of circular path.

Equating the 2 forces , we get -

\frac{mv^{2} }{r} = kmg

∴ v = \sqrt{krg}

Substituting all the values , we get -

v = 13.7 m/s.

5 0
3 years ago
Please really need help with this one <br> A <br> B<br> C<br> D
Stella [2.4K]

d thought i wouldnt trust me on it

7 0
3 years ago
What would be the formula if you<br> wanted to solve for the<br> acceleration?
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Answer:

acceleration = final velocity - initial velocity / time

V-U/T

Explanation:

Acceleration (a) is the change in velocity (Δv) over the change in time (Δt), represented by the equation a = Δv/Δt.

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3 years ago
What can you conclude about this product?
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