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Nikitich [7]
2 years ago
5

PLEASE HELP!!! Will give brainliest!

Physics
2 answers:
Contact [7]2 years ago
8 0

The answer is B, Both can be characterized by amplitude, frequency, and wavelength. the speed of both is affected by the medium through which it travels.


Natali5045456 [20]2 years ago
3 0

The correct answer to the question will be B) Both can be characterized by amplitude, frequency, and wavelength. The speed of both is affected by the medium through which it travels.

EXPLANATION:

Light is an electromagnetic wave which is transverse in nature. It contains both the electric field and magnetic field which are perpendicular to each other as well as perpendicular to the direction of propagation.

We know that a transverse wave is characterized by its amplitude, frequency and wavelength . Here, crests and troughs are created which give the idea about the wavelength . The distance between two successive crests or troughs is called wavelength.

A sound wave is a longitudinal wave which moves in the form of compressions and rarefactions. Compressions are the high pressure zones while rarefactions are the low pressure zones in the wave. Here, the distance between two successive compresions or rarefactions is called wavelength of the wave. It is also characterized by frequency and amplitude.

The speed of light is medium dependent . It is more in optically rarer medium while less in optically denser medium . The light does not  require any medium for its propagation. It may propagate through space where it has the maximum velocity.

The speed of sound is also medium dependent . It depends on the density and elasticity of the medium.It can not travel through vacuum. It needs a medium for its propagation.

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An object is 70 um long and 47.66um wide. how long and wide is the object in km?​
Ganezh [65]

Answer:

length =  7*10^(-8)km

width = 4.666*10^(-8) km

Explanation:

We know that:

1 μm = 1*10^(-6) m

and

1km = 1*10^3 m

or

1m = 1*10^(-3) km

if we replace the meter in the first equation, we get:

1 μm = 1*10^(-6)*1*10^(-3) km

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Now with this relationship we can transform our measures:

Length: 70 μm is 70 times 1*10^(-9)km, or:

L = 70*1*10^(-9)km = 7*10^(-8)km

And for width, we have 47.66um, this is 46.66 times 1*10^(-9)km, or:

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7 0
2 years ago
A 0.700-kg particle has a speed of 1.90 m/s at point circled A and kinetic energy of 7.20 J at point circled B. (a) What is its
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Answer:

a). E_{kA}=1.2635 J

b). V_{B}=4.535\frac{m}{s}

c). ΔE_{t}=8.4635 J

Explanation:

ΔE=kinetic energy

a).

E_{kA}=\frac{1}{2}*m*v_{A} ^{2} \\ v_{A}=1.9 \frac{m}{s}\\ m=0.70kg\\E_{kA}=\frac{1}{2}*0.70kg*(1.9 \frac{m}{s})^{2} \\E_{kA}=1.2635 J

b).

E_{kB}=\frac{1}{2}*m*v_{B} ^{2}

V_{B}^{2}=\frac{E_{kB}*2}{m} \\V_{B}=\sqrt{\frac{E_{kB}*2}{m}} \\V_{B}=\sqrt{\frac{7.2J*2}{0.70kg}} \\V_{B}=4.53 \frac{m}{s}

c).

net work= EkA+EkB

E_{t}=E_{kA}+ E_{kB}\\E_{t}=1.2635J+7.2J\\E_{t}=8.4635J

3 0
3 years ago
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