Here, g is the acceleration due to gravity at the Earth's surface and is the standard gravity, defined as 9.8m/s....So, the force by that gravity is called g-force.....

3 0

3 years ago

If I am plotting a graph to my physics practical result. If they ask me to find the x-intercept, what should I consider when plo

Virty [35]

Answer:

• When getting x-intercept, your vertical axis or y-axis must have it's callibration and demarcation starting from zero.

Explanation:

As well as when getting y-intercept, your horizontal axis or x-axis must have it's callibration and demarcation starting from zero.

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7 0

2 years ago

A football player punts the ball from the ground at a 65.0° angle above the horizontal. If the ball stays in the air for a total

maw [93]

Answer: $V_{0,x } = 297.7 \frac{m}{s}\\V_{0,y } = 637 \frac{m}{s}$

Explanation:

Hi!

We define the point (0,0) as the intial position of the ball. The initial velocity is $(V_{0,x}, V_{0,y})$

The motion of the ball in the horizontal direction (x) has constant velocity, because there is no force in that direction. :

$x(t) = V_{0,x}t$

In the vertical direction (y), there is the downward acceleration g of gravity:

$y(t) = -gt^2 + V_{0,y}t$

(note the minus sign of acceleration, because it points in the negative y-direction)

When the ball hits the ground, at t = 65s, y(t = 65 s) = 0. We use this to find the value of the initial vertical velocity:

$0 = t(-gt + V_{0,y})\\V_{0,y} = gt = 9.8 \frac{m}{s^2} 65 s = 637 \frac{m}{s}$

We used that g = 9.8 m/s²

To find the horizonttal component we use the angle:

$\tan(65\º) = \frac{V_{y,0}}{V_{x,0}} = 2.14\\V_{x,0} = 297.7\frac{m}{s}$

5 0

2 years ago

5. A man pulls down on a rope to hoist a sail on a sailboat. This is an example of a machine

tino4ka555 [31]

B. changing the direction over which a force is exerted

5 0

2 years ago