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Sidana [21]
3 years ago
5

If two planets orbit a star, but planet B is twice as far from the star as planet A, planet A will receive ____ times the flux t

hat planet B receives.
Physics
1 answer:
Tresset [83]3 years ago
7 0

Answer:

The nearest plant (A) receives 4 times more radiation from the farthest plant

Explanation:

The energy emitted by the star is distributed on the surface of a sphere, whereby intensity received is the power emitted between the area of ​​the sphere

                I = P / A

               P = I A

The area of ​​the sphere is

               A = 4π r²

Since the amount of radiation emitted by the star is constant, we can write this expression for the position of the two planets

               P = I₁ A₁ = I₂ A₂

               I₁ / I₂ = A₂ / A₁

 Suppose index 1 corresponds to the nearest planet,

            r2 = 2 r₁

            I₁ / I₂ = r₁² / r₂²

            I₁ / I₂ = r₁² / (2r₁)²

            I₁ / I₂ = ¼

           4 I₁ = I₂

The nearest plant (A) receives 4 times more radiation from the farthest plant

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The Michelson-Morley experiment a) confirmed that time dilation occurs. b) proved that length contraction occurs. c) verified th
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e) indicated that the speed of light is the same in all inertial reference frames.

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5 0
3 years ago
Given two vectors A=4i^+3j^ and vector<br> B=5i^-2j^.find the magnitude of each vector
Flura [38]

Answer:

<em>Magnitude of A=5</em>

<em>Magnitude of B=5.39</em>

Explanation:

<u>The magnitude of Vectors in Rectangular Form</u>

Given a vector v in its rectangular form:

\mathbf{v}=x\hat i+y\hat j

The magnitude of v is:

\mid\mid\mathbf{v}\mid \mid=\sqrt{x^2+y^2}

We are given the vectors

\mathbf{A}=4\hat i+3\hat j

\mathbf{B}=5\hat i-2\hat j

Their magnitudes are:

\mid\mid\mathbf{A}\mid \mid=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}

\mid\mid\mathbf{A}\mid \mid=5

\mid\mid\mathbf{B}\mid \mid=\sqrt{5^2+(-2)^2}=\sqrt{25+4}=\sqrt{29}

\mid\mid\mathbf{B}\mid \mid=\sqrt{29}=5.39

4 0
3 years ago
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