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Elden [556K]
3 years ago
11

If two deuterium nuclei (charge +e, mass 3.34×10−27kg) get close enough together, the attraction of the strong nuclear force wil

l fuse them to make an isotope of helium, releasing vast amounts of energy. The range of this force is about 10−15. This is the principle behind the fusion reactor. The deuterium nuclei are moving much too fast to be contained by physical walls, so they are confined magnetically. (a) How fast would two nuclei have to move so that in a head-on collision they would get close enough to fuse? (Assume their speeds are equal. Treat the nuclei as point charges, and assume that a separation of 1.0×10−15 is required for fusion.) (b) What strength magnetic field is needed to make deuterium nuclei with this speed travel in a circle of diameter 2.50 m?

Physics
1 answer:
Zina [86]3 years ago
7 0

Answer:

<u>note:</u>

<u><em>solution is attached due to error in mathematical equation. please find the attachment</em></u>

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How do leptons differ from hadrons?
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I'll just give you the link for it but count it as my answer. http://www.differencebetween.com/difference-between-leptons-and-vs-hadrons/
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3 years ago
A car travels 2155.0m in 195.9s. What is the car's average speed?
inna [77]

Average speed of the car is 11 m/s

Explanation:

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Speed of the car = 2155/195.9 = 11 m/s

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3 years ago
Most of the really bright stars in our sky are NOT among the stars that are very close to us. Why then do they look so bright to
Yanka [14]

Answer:

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Explanation:

Luminous refers to..,

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Most of the really bright stars in our sky are not that very close to us yet they look bright because of the Luminosity of the star.

These stars are intrinsically so luminous.

A star's power output across all wavelengths is called its bolometric luminosity.

A star with large luminosity will have more measure of radiated electromagnetic power meaning.

so it will emit more light than a low luminosity star.

Hence,

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learn more about  Luminosity of the star here:

<u>brainly.com/question/13912549</u>

<u />

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6 0
2 years ago
Consider a double slit experiment in the air. The wavelength of light is 500nm light, the screen is 1m away and two adjacent bri
Bess [88]

Answer: 0.75\ cm

Explanation:

Given

Wavelength of light \lambda=500\ nm

Screen is D=1\ m away

Distance between two adjacent bright fringe is \Delta y=\dfrac{\lambda D}{d}

When same experiment done in water, wavelength reduce to \dfrac{\lambda }{\mu}

So, the distance between the two adjacent bright fringe is \Delta y'=\dfrac{\lambda D}{\mu d}

Keeping other factor same, distance becomes

\Rightarrow \dfrac{1}{\frac{4}{3}}=\dfrac{3}{4}\quad \text{Refractive index of water is }\dfrac{4}{3}\\\\\Rightarrow 0.75\ cm

3 0
3 years ago
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