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Scorpion4ik [409]
3 years ago
11

An 80-kg firefighter slides down a fire pole. After 1.3 seconds of sliding, the firefighter is sliding at a velocity of 6.5 m/s,

straight down the pole. Once this velocity is reached, the firefighter grips the pole so that the force of friction exerted by the firefighter's hands on the pole is equal to the force of gravity. At this point what is the downward acceleration of the firefighter
Physics
1 answer:
yuradex [85]3 years ago
5 0

Answer:

a= 0

Explanation:

  • In the vertical direction, if the friction force (directed upward) is equal to the force of gravity (downward) this means that no net force is acting on the firefighter.
  • According to Newton's 2nd Law, if no net force is present, the acceleration in this direction is just zero, as follows:

       F_{net} = m*a = 0  (1)

      ⇒ a = 0

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Part 1)

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How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns
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Complete Question

How many turns are in its secondary coil, if its input voltage is 120 V and the primary coil has 210 turns.

The output from the secondary coil is  12 V

Answer:

The value  is  N_s  =  21 \  turns

Explanation:

From the equation we are told that

   The input voltage is  V_{in}  = 120 \ V

   The number of turns of the primary coil is N_p =  210 \  turn

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   \frac{N_p}{V_{in}}  =\frac{N_s}{V_o}

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=>N_s  =  \frac{210}{120}  *  12

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