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Scorpion4ik [409]
3 years ago
11

An 80-kg firefighter slides down a fire pole. After 1.3 seconds of sliding, the firefighter is sliding at a velocity of 6.5 m/s,

straight down the pole. Once this velocity is reached, the firefighter grips the pole so that the force of friction exerted by the firefighter's hands on the pole is equal to the force of gravity. At this point what is the downward acceleration of the firefighter
Physics
1 answer:
yuradex [85]3 years ago
5 0

Answer:

a= 0

Explanation:

  • In the vertical direction, if the friction force (directed upward) is equal to the force of gravity (downward) this means that no net force is acting on the firefighter.
  • According to Newton's 2nd Law, if no net force is present, the acceleration in this direction is just zero, as follows:

       F_{net} = m*a = 0  (1)

      ⇒ a = 0

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Answer:

2.7%,Almost three percent of adolescents

Explanation:

The two most common eating disorders are anorexia nervosa and bulimia what percentage of American adolescents have experienced anorexia nervosa or bulimia

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A football field lies so one endzone is to the east and one is to the west. A running back gets the ball and starts running 20o
Jobisdone [24]

Answer:

( 80.87 i - 12.96 j ) m

Explanation:

Running back movements :

20⁰ north of east  for  10 meters,  

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A) show vector pointing from the starting point to the end ( where he scored )

The final vector displacement : ( 80.87 i - 12.96 j ) m

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attached below is the required  diagram

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3 years ago
A shopping cart is initially at rest when it undergoes a constant acceleration. After
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What is the electric field at the point x=6.5 m? positive e-fields point to the right.?
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3 years ago
a basketball player can leap upward .65m how long does the basketball player remain in the air use 9.81m/s²​
tigry1 [53]

At the player's maximum height, their velocity is 0. Recall that

{v_f}^2-{v_i}^2=2a\Delta y

which tells us the player's initial velocity v_i is

0^2-{v_i}^2=-2g(0.65\,\mathrm m)\implies v_i=3.6\dfrac{\rm m}{\rm s}

The player's height at time t is given by

y=v_it-\dfrac g2t^2

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0.65\,\mathrm m=\left(3.6\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2\implies t=0.36\,\mathrm s

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