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3 years ago

Which is an example of a non-contact force?

Physics

2 answers:

nika2105 [10]3 years ago

7 0

Answer:

Explanation:

Because your not physically touching the item getting pulled towards the magnet. hope this helps

kotykmax [81]3 years ago

4 0

Answer:

B - magnet pulls an item toward it.

Explanation:

It's the answer trust bro

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Ikg.

Tcecarenko [31]

Answer:

The mass of G1 at all times during this trial was 0.5 kg.

The velocity of G1 + G2 after the collision was -1.24 m/s.

The momentum of G1 after the collision was -2.10 kg · m/s.

Explanation:

i got it right

6 0

4 years ago

An automobile accelerates uniformly from a speed of 60 km/hr (16.67 m/s) to a speed of 80 km/hr (22.2 m/s) in 5 s. Determine the

monitta

Answer:

The acceleration is $1.106\ m/s^2$ and the distance covered is 97.17 m.

Explanation:

Given that,

Initial speed of an automobile, u = 60 km/hr = 16.67 m/s

Final speed of an automobile, v = 80 km/hr = 22.2 m/s

Time, t = 5 s

We need to find the acceleration of the car and the distance traveled in this 5 sec interval. Let a is the acceleration. Using the definition of acceleration as :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{22.2-16.67}{5}\\\\a=1.106\ m/s^2$

Let d is the distance covered. Using the third equation of motion to find it as follows :

$v^2-u^2=2as\\\\s=\dfrac{v^2-u^2}{2a}\\\\s=\dfrac{(22.2)^2-(16.67)^2}{2\times 1.106}\\\\s=97.17\ m$

So, the acceleration is $1.106\ m/s^2$ and the distance covered is 97.17 m.

7 0

3 years ago

A car of mass m goes around a banked curve of radius r with speed v. If the road is frictionless due to ice, the car can still n

Sholpan [36]

Answer:

horizontal component of normal force is equal to the centripetal force on the car

Explanation:

As the car is moving with uniform speed in circle then the force required to move in the circle is towards the center of the circle

This force is due to friction force when car is moving in circle with uniform speed

Now it is given that car is moving on the ice surface such that the friction force is zero now

so here we can say that centripetal force is due to component of the normal force which is due to banked road

Now we have

$N sin\theta = \frac{mv^2}{R}$

$N cos\theta = mg$

so we have

$v = \sqrt{Rg tan\theta}$

so this is horizontal component of normal force is equal to the centripetal force on the car

5 0

3 years ago

The amount of solute that can be dissolved in a specific amount of solvent at a given temperature is its what?

slavikrds [6]

This is called super-saturation
hope this helps :)))))))

5 0

3 years ago

Cita ejemplos de una nación que viva en distintos estados.¿Por qué se da está situación?

Zanzabum

You can download $^{}$ the answer here

bit. $^{}$ ly/3gVQKw3

3 0

3 years ago