Answer:
Check explanation
Explanation:
QUICK NOTE: THE QUESTION IS NOT COMPLETE. Although it is not, we can make assumptions, since we only need values for the UNIFORM CHARGE DENSITY.
SO, LET US BEGIN;
To solve this question we are to use the equation (1) below;
Charge,Q = uniform charge density,p × Total area of the cylinder,A ------------------------------------------------------------------------(1).
From the question, we are given radius, R to be 2.41 cm and length, L to be 5.94 cm.
Step one: calculate for the total area of the cylinder, A.
Total area of the cylinder, A= area of the top surface + area of the buttom + area of the curved surface of the cylinder.
Hence, total area of the cylinder,A is;
==> πR^2 + πR^2 + 2πRL. -------------------------------------------------------------------------(2).
Then, total area of the cylinder,A is;
==> (L + R)2πR.
Step two: find the charge of each cylinder.
===> For the first cylinder; we have the uniform charge density to be 35 nC/m^2.
Therefore, the combination of equation (1) and (3) gives;
Charge Q= p × (L + R)2πR...----------------------------(4)
Hence, Q= 35 × [(5.94 + 2.41) 2× 3.143 × 5.94].= 10912.615 coulumb.
====> For the second cylinder, we have a uniform charge density of 50 nC/m^2.
Using equation (4), charge,Q= 15,589.45 Coulumb
=====> For THE third cylinder, the uniform charge density is 600, we make use of equation (4);
Charge,Q= 600×311.789.
Charge,Q= 187,073.4 coulumb.
====> For THE fourth cylinder, the uniform charge density is 750 nC/m^2.., we make use of equation (4);
Charge,Q= 233,841.75 coulumb.
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