Convergent faults ____

Why is friction like applied force but different from gravity?

kirill115 [55]

Answer:

Friction is when a force is applied or done by weight dragging onto something.

Explanation:

Gravity is when an object is getting pulled toward the center of what is attracting it. And applied force is when someone/sommething is applying force.

3 0

3 years ago

Read 2 more answers

The owners want the speed at the bottom of the first hill doubled. How much higher must the first hill be built?

Sonja [21]

Neglecting friction and air resistance, the first hill must be built 4 times higher than it is now.

3 0

3 years ago

3kg of water at 80degree celcius is added to 8 kg of water at 25 degree celcius. find the temperature of final mixture provided

Nitella [24]

Answer:

hope fully it help s

3 0

2 years ago

A uniform marble rolls down a symmetrical bowl, start- ing from rest at the top of the left side. The top of each side is a dist

Paha777 [63]

Answer:

Part a)

$h' = \frac{10}{14} h$

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

$h' = \frac{10}{14} h$

so on smooth it will go to lower height

Explanation:

As we know by energy conservation the total energy at the bottom of the bowl is given as

$\frac{1}{2} mv^2 + \frac{1}{2}I\omega^2 = mgh$

here we know that on the left side the ball is rolling due to which it is having rotational and transnational both kinetic energy

now on the right side of the bowl there is no friction

so its rotational kinetic energy will not change and remains the same

so it will have

$\frac{1}{2}mv^2 = mgh'$

now we know that

$I = \frac{2}{5}mr^2$

$\omega = \frac{v}{r}$

so we have

$\frac{1}{2}mv^2 + \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = mgh$

$\frac{1}{2}mv^2 + \frac{1}{5}mv^2 = mgh$

$\frac{7}{10}mv^2 = mgh$

$\frac{1}{2}mv^2 = \frac{10}{14}mgh$

so the height on the smooth side is given as

$h' = \frac{10}{14} h$

Part b)

if both sides are rough then it will reach the same height on the other side because the energy is being conserved.

Part c)

Since marble will go to same height when it is rough while when it is smooth then it will go to the height

$h' = \frac{10}{14} h$

so on smooth it will go to lower height

6 0

3 years ago

Read 2 more answers

Effects of the earths orbit around the sun

makvit [3.9K]

<h3><u>Effects of the earths orbit around the sun:</u></h3>

The earth moves around the sun in an elliptical orbit, Johannes Kepler, a "German mathematician, and astronomer" described this elliptical orbit first. The orbit is close to being a circle but not a circle. Earth orbiting the sun mainly effects on seasons on earth.

Earth's four seasons are determined when Earth is tilted 23.4 degrees on the vertical axis, which is called as “axial tilt”. When a "southern hemisphere is tilted towards the sun", it experiences summer and northern hemisphere experiences winter, exactly opposite happens when northern hemisphere tilts towards Sun and this climate change goes on in all countries.

7 0

3 years ago

Convergent faults _____.