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Dahasolnce [82]

3 years ago

7

An ant can travel approximately 30 meters per minute. How many meters could an ant move in 45 minutes?

2 answers:

krek1111 [17]3 years ago

8 0

Answer:

about 50 meters to 60 meters I'm sorry if its not right.

kotegsom [21]3 years ago

8 0

Answer:

1350

Explanation:

30x45

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What is the connection between electrons and protons

TEA [102]

Answer:

Electrons and protons are connected with one another in term of charge and size.

Explanation:

The size of electron and proton is always same in any atom but they possess opposite charge.
Electron in any atom carries negative charge where as proton carries the positive charge.
In any neutral atom the charge between electron and proton is balanced along with the size.
The nucleus of any atom bounds only proton and neutron but the electron is present revolving around the nucleus.

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Which one of the following substances is a liquid fuel used in rocket engines?

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The answer is, "B", "Ammonia".

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3 years ago

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A beam of light, initially travelling in the air, strikes water surface at an angle of 24.5° with the normal. If the speed of li

kykrilka [37]

Answer:

Explanation:

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3 years ago

determine the force of gravitational attraction between a 78kg boy sitting 2 meters away from a 65kg girl.

bixtya [17]

Answer:

$F=8.45\times 10^{-8}\ N$

Explanation:

Given that,

Mass of a boy is 78 kg

Mass of a girl is 65 kg

We need to find the force of gravitational attraction between them if they are 2 m away.

The formula for the gravitational force is given by :

$F=\dfrac{Gm_1m_2}{r^2}\\\\F=\dfrac{6.67\times 10^{-11}\times 78\times 65}{(2)^2}\\\\=8.45\times 10^{-8}\ N$

So, the force between them is $8.45\times 10^{-8}\ N$ .

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3 years ago

What is the magnitude of the electric field at a distance of 89 cm from a 27 μC charge, in units of N/C?

GuDViN [60]

Answer:

306500 N/C

Explanation:

The magnitude of an electric field around a single charge is calculated with this equation:

$E(r) = \frac{1}{4 \pi *\epsilon 0} \frac{q}{r^2}$

With ε0 = 8.85*10^-12 C^2/(N*m^2)

Then:

$E(0.89) = \frac{1}{4 \pi *8.85*10^-12} \frac{27*10^-6}{0.89^2}$

E(0.89) = 306500 N/C

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3 years ago