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jok3333 [9.3K]
3 years ago
13

Part 1: In two or more complete sentences, explain how to find the probability of being dealt three kings from a standard deck o

f 52 cards when three cards are dealt. In your final answer, include all necessary steps and calculations.
Part 2: In two or more complete sentences, make a decision and support your position: Is Pascal’s triangle an appropriate method to determine the probability in Part 1?
Mathematics
2 answers:
Ne4ueva [31]3 years ago
7 0
1) We have that there are (52,3) ways to pick 3 cards out of 52 cards. Also, there are (4,3) ways to pick 3 kings out of the 4 total available kings in the deck.  In essence, we need to have one of those ways to be the selected 3 cards. Hence, the probability is the ration (4,3)/(52,3). Computing this:
P=\frac{1*2*3*4}{(1*2*3)*1} /  \frac{52*51*50}{1*2*3} = \\  \frac{4*1*2*3}{52*51*50}=0.0181%
The probability is very low but not negligible.

2) The Pascal triangle defines a recursive relationship. Hence, we would need to calculate all the binomial coefficients up to 51. Thus, it is not at all practical to use the Pascal Triangle to calculate the ways. It is easier to do the direct computation.
ozzi3 years ago
3 0

Answer with explanation:

Part 1

Number of Kings in the deck of 52 card =4 kings

Number of ways of selecting 3 kings from 4 kings

                           =_{3}^{4}\textrm{C}\\\\=\frac{4!}{(4-3)!\times 3!}\\\\=\frac{4 \times 3!}{3!}\\\\=4    

Probability of an event

                        =\frac{\text{Total favorable outcome}}{\text{Total Possible Outcome}}

Probability of selecting three kings from a standard deck of 52 cards

                           =\frac{_{3}^{4}\textrm{C}}{_{3}^{52}\textrm{C}}\\\\=\frac{4}{\frac{52!}{49!*3!}}\\\\=\frac{4}{22100}\\\\=\frac{1}{5525}

Part 2:  

When you use the word Pascal's triangle , it is used to expand the expansion containing two or more terms having whole term raised to power n, where n is a positive Integer.No, Pascal's triangle is not an appropriate method to determine the probability in Part 1.It will be Lengthier.                            

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At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

<h3>How to state hypothesis conclusion?</h3>

We are given;

Sample size; n = 78

population standard deviation σ = 37

Sample Mean; x' = 280

Population mean; μ = 287

The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;

Null hypothesis; H₀: μ > 280

Alternative hypothesis; Hₐ: μ < 280

This is a one tail test with significance level of α  = 0.13

From online tables, the critical value at α  = 0.13 is z(c) = -1.13

b) Formula for the test statistic is;

z = (x-  μ)/(σ/√n)

z = ((280 - 287) *√78 )/37

z = -1.67

c) From online p-value from z-score calculator, we have;

P[ z > 280 ] =  0.048

d) The value for z = -1.67  is smaller than the critical value mentioned in problem statement z(c) = - 1.13  , the z(s) is in the rejection zone. Therefore we reject H₀

e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

Read more about Hypothesis Conclusion at; brainly.com/question/15980493

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