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Vilka [71]
3 years ago
8

Which situation can be modeled by the inequality 60−15x≥760-15x≥7?                            1 )You borrowed $60 from your olde

r brother. You pay him $7 a week and need to pay him back within 15 weeks                                                                                                        2 )You owe your parents $60 and plan to pay them $15 a week until you owe them less than $7.                                                                                                                 3 ) You can buy playlists in packages of 15 songs. You have $60 to spend but want to have at least $7 left.                                                                                           4)You have $60 to spend on hats at the mall, but you need to save at least $7 for lunch. You plan to spend the rest on hats that cost $15 each (including tax).                                                                                                                              
Mathematics
1 answer:
aliina [53]3 years ago
5 0
The answer is number 4 "You have $60 to spend on hats at the mall, but you need to save at least $7 for lunch. You plan to spend the rest on hats that cost $15 each including tax"
60-$15x refers to "you have $60 to spend on hats" and "to spend the rest on hats" while <7 for ''save at least $7 for lunch"

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What is the answer to 9 over 15= 3 over 5
Ksenya-84 [330]

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2 25/100

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In order to determine the average price of hotel rooms in Atlanta, a sample of 64 hotels was selected. It was determined that th
deff fn [24]

Answer:

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

Step-by-step explanation:

From the question we are told that

   The sample size is  n = 64

    The average price is  \= x  = \$ 112

    The population standard deviation is  \sigma  = \$ 16

     The level of significance is  \alpha  = 0.05

    The population mean is  \mu = \$ 108.5

The null hypothesis is  H_o :  \mu = 108.50

The alternative hypothesis is  H_a  :  \mu \ne  108.50

Generally the test statistics is mathematically represented as

       z = \frac{\= x - \mu }{ \frac{ \sigma}{\sqrt{n} } }

=>    z = \frac{112 - 108.50 }{ \frac{ 16}{\sqrt{64} } }  

=>    z = 1.75

From the z table  the area under the normal curve to the left corresponding to  1.75  is  

       P( Z >  1.75) = 0.040059

Generally  p-value is mathematically represented as

        p-value = 2 * P( Z >  1.75)

=>     p-value = 2 * 0.040059

=>     p-value = 0.08012

From the values obtained we see that  p-value  > \alpha hence

The decision rule is  

Fail to reject the null hypothesis

The conclusion is  

There is no sufficient evidence to show that the average room price is significantly different from $108.50

 

3 0
3 years ago
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