A) the final velocity = 66/9 m/s.
b) The total momentum before and after collision is the same because energy is destroyed or made.
Thanks brainly. <span />
I don’t really know the answer cause I need more information about the question
Answer:
13 m/s^2
Explanation:
The acceleration of gravity near the surface of a planet is:
g = MG / R^2
For planet 1, g = 26 m/s^2.
The gravity on planet 2 in terms of the mass and radius of planet 1 is:
g = (2M)G / (2R^2)
g = 1/2 MG / R^2
Since MG/R^2 = 26 m/s^2, then:
g = 13 m/s^2
Answer:
Explanation:
Given that,
Initial speed of the girl is
u = 1.4m/s
Height she is going is
H = 2.45m
Incline plane she will pass to that height
L = 12.4m
Mass of girl and bicycle is
M=60kg
Frictional force that oppose motion is
Fr = 41N
Speed at lower end of inclined plane
V2 = 6.7m/s
Work done by the girl when the car travel downward
Using conservation of energy
K.E(top) + P.E(top) + work = K.E(bottom) + P.E(bottom) + Wfr
Where Wfr is work done by friction
Wfr = Fr × d
P.E(bottom) is zero, sicne the height is zero at the ground
K.E is given as ½mv²
Then,
½M•u² + MgH + W = ½M•V2² + 0 + Fr×d
½ × 60 × 1.4² + 60×9.8 × 2.45 + W = ½ × 60 × 6.7² + 41 × 12.4
58.8 + 1440.5 + W = 1855.1
W = 1885.1 —58.8 —1440.5
W = 355.8 J
Answer:
ac = 27.22 m/s
Explanation:
ac=v^2/r
m=2500kg
v=35 m/s
Fc=mv^2/r
I'm not sure why you would need mass but I will solve for Fc aswell
Ac=35^2/45 = 1225/45= 27.22 m/s
Fc= 2500(27.22)=68050 N
