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solniwko [45]
3 years ago
14

A car goes forward along a level road at constant velocity. The additional force needed to bring the car into equilibrium is

Physics
1 answer:
liraira [26]3 years ago
8 0

Answer: Frictional force

Explanation:

Since the body is moving at constant velocity, this means that the acceleration of the body is zero. Frictional force is a force of opposition which tends to oppose the moving force of an object on a flat surface.

Mathematically, summation of force on the car along the road will be

Fm - Ff = ma

Fm = moving force

Ff = frictional force

m = mass of the body

a = acceleration of the body

Since a = 0, we have;

Fm -Ff = 0

Fm = Ff (which shows that the two forces acting on the body are equal and opposite)

This frictional force will tend to keep the body at equilibrium.

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Raul wants to study how pot size affects the growth of plants. To do this, he intends to purchase three different pots of varyin
hram777 [196]

Answer: The answer position may vary. But the correct answer is D. No; Raul changes more than one variable so the results will be invalid.

Explanation:

Raul's experimental set-up will not produce valid results because he intends to change more than one variable.

One variable that Raul will change is the pot size. According to the description, however, Raul will also change one other variable—the type of flower that is planted. Even though Raul plans on using flowers only, he should use the same type of flower in each pot, not different types.

Valid results are only produced when only one variable is changed at a time.

5 0
4 years ago
Read 2 more answers
A paintball is shot horizontally in the positive x direction at time t after the ball is shot it is 4 cm to the right and 4 cm b
Artist 52 [7]

<u>Answer:</u>

At time 2t the paint ball is at 8 cm to the right and 16 cm to the bottom

<u>Explanation:</u>

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Considering the horizontal motion of paint ball

    Distance traveled during time t = 4 cm

    Initial velocity = u m/s

   Acceleration = 0 m/s^2

So 4 = u*t+\frac{1}{2} *0*t^2\\ \\ u = \frac{4}{t}

Now at time 2t,

  S= u*2t+\frac{1}{2} *0*(2t)^2\\ \\=\frac{4}{t} *2t\\ \\ =8cm

  So horizontal distance traveled in time 2t = 8 cm to the right

Now considering the vertical motion of paint ball

  Distance traveled during time t = 4 cm

    Initial velocity = 0 m/s

   Acceleration = -g m/s^2

4=0*t-\frac{1}{2} *g*t^2\\ \\ t^2=\frac{-8}{g}

At time 2t,

     S=0*2t-\frac{1}{2} *g*(2t)^2\\ \\ =-\frac{1}{2} *g*4*\frac{-8}{g}\\ \\ =16 cm

 So vertical distance traveled in time 2t = 16 cm to the bottom

 

6 0
3 years ago
Suppose a standing wave created on a spring that is 10.5 m long has a speed of 14 m/s and a frequency of 2 Hz. How many nodes an
dimulka [17.4K]

Answer:

If the two waves have the same amplitude and wavelength, then they alternate between ... In fact, the waves are in phase at any integer multiple of half of a period: ... The propagation velocity of the waves is 175 m/s.

Explanation:

please ask me in brainlist ok

6 0
3 years ago
If a transformer has 50 turns in the primary winding and 10 turns on the secondary winding, what is the reflected resistance in
Elza [17]

Answer:

The reflected resistance in the primary winding is 6250 Ω

Explanation:

Given;

number of turns in the primary winding, N_P = 50 turns

number of turns in the secondary winding, N_S = 10 turns

the secondary load resistance, R_S = 250 Ω

Determine the turns ratio;

K = \frac{N_P}{N_S} \\\\K = \frac{50}{10} \\\\K = 5

Now, determine the reflected resistance in the primary winding;

\frac{R_P}{R_S} = K^2\\\\R_P = R_SK^2\\\\R_P = 250(5)^2\\\\R_P = 6250 \ Ohms

Therefore, the reflected resistance in the primary winding is 6250 Ω

6 0
3 years ago
What’s the answer to this question
alexgriva [62]

Answer:

space = 66.24 [m]

Explanation:

To solve this problem we must remember that the average speed is defined as the relationship between a space traveled over a certain time.

Av = \frac{space}{time}

where:

space [m]

Av = average velocity = 3.6 [m/s]

time = 18.4 [s]

space = 3.6*18.4\\space = 66.24 [m]

7 0
3 years ago
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