Answer:
The answer is 80 kN . m (clockwise)
Explanation:
As,
M = P x L
Here, the towline exerts a force is P.
Substituting P for 4000N.
M = -4000N x 20m
= -80000N.m
= 80kN.m
Maximum moment about the point O is 80kN.m (Clockwise)
Answer:
The electric force acting on the raindrop is 100 N.
Explanation:
Given;
charge of the raindrop, Q = 10 mC = 0.01 C
electric field strength, E = 10,000 V/m = 10,000 N/C
The force acting on the raindrop is given as;
Electric Force = electric field strength x charge of the raindrop
F = EQ
F = (10,000 N/C) (0.01 C)
F = 100 N
Therefore, the electric force acting on the raindrop is 100 N.
Given: Mass m = 290 Kg; Height h = 7 m
Required: Work = ?
Formula: Work = Force x distance but, Force F = mg
W= fd
W = mgh
W= (290 Kg)(9.8 m/s²)(7 m)
W = 19,894 Kg.m²/s²
W = 19,894 J
Mechanical energy (ME) is the sum of potential energy (PE) and kinetic energy (KE). When the toy falls, energy is converted from PE to KE, but by conservation of energy, ME (and therefore PE+KE) will remain the same.
Therefore, ME at 0.500 m is the same as ME at 0.830 m (the starting point). It's easier to calculate ME at the starting point because its just PE we need to worry about (but if we wanted to we could calculate the instantaneous PE and KE at 0.500 m too and add them to get the same answer).
At the start:
ME = PE = mgh
ME = 0.900 (9.8) (0.830)
ME = 7.32 J
