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3 years ago

A toy car with an initial velocity of 5 m/s slows to a stop with an acceleration of -1.5 m/s^2.

Physics

1 answer:

enot [183]3 years ago

4 0

Car's Initial velocity (u) = 5 m/s

Car's Final velocity (v) = 0 m/s (Stop)

Acceleration of the car (a) = -1.5 m/s²

Equation used to solve this problem:

$\boxed{ \bf{ {v}^{2} = {u}^{2} + 2as}}$

By substituting values in the equation, we get:

$\rm \longrightarrow {0}^{2} = {5}^{2} +2 \times ( - 1.5) \times s \\ \\ \rm \longrightarrow 0 = 25 - 3s \\ \\ \rm \longrightarrow 25 - 3s = 0 \\ \\ \rm \longrightarrow 25 - 25 - 3s =0 - 25 \\ \\ \rm \longrightarrow - 3s = - 25 \\ \\ \rm \longrightarrow 3s = 25 \\ \\ \rm \longrightarrow \dfrac{3s}{3} = \dfrac{25}{3} \\ \\ \rm \longrightarrow s = 8.3 \: m$

$\therefore$ Displacement of the toy car (s) = 8.3 m

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