Question

Determine the shortest frequency of light required to remove an electron from a sample of ti metal if the binding energy of titanium is 3.14 × 103 kj/mol.

Answer 1

The correct answer is: shortest frequency = 7.86*10^15 $s^{-1}$

Explanation: 
The binding energy of titanium = 3.14*10^6 J/mol
The energy required to remove an electron = (3.14*10^6) /(6.023*10^23) = 5.213*10^-18 J
Where 6.023*10^23 = Avagadro number

Since E = hv

Frequency = v = E/h
E = Energy = 5.213*10^-18
h = Planck's constant = 6.626*10^-34
v = (5.213*10^-18) / 6.626*10^-34)
v = 7.86*10^15 $s^{-1}$ (shortest frequency)