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dangina [55]
3 years ago
10

Assinale a alternativa incorreta. *

Chemistry
1 answer:
MakcuM [25]3 years ago
3 0

Answer:

<u>The incorrect choice is the last one:</u>

  • <em>In the Leucipo and Democritus atomic model, electrons had negative charges.</em>

Explanation:

The translation of the question is:

Choose the incorrect statement. *

  • Matter is everything that has mass and occupies volume.

  • Mass and weight are different quantities. Mass is a measure of how much matter an object has, and weight is a measure of the gravitational pull force suffered by the object.

  • Dalton's atomic model has similarities to the atomic model described by Leucipo and Democritus.

  • Dalton thought that atoms of the same element could not combine, as they developed mutual repulsion.

  • In the Leucipo and Democritus atomic model, electrons had negative charges.

<h2>Solution</h2>

The <em>last statement is false</em> because Leucipo and Democritus thought that the atom was an indivisible particle. This is, they did not think there were subatomic particles, such as electrons. Furthermore, the idea of a particle with a negative charge was developed much time (centuries) later.

As for the other statements:

  • <em>Matter is everything that has mass and occupies volume</em>: this is the current definition of matter; for instance, wood, air, atoms, have mass and occupy volume. Thougths, feelings do not have either mass or occupy a volume, they are not matter.

  • <em>Mass and weight are different quantities</em>. <em>Mass is a measure of how much matter an object has, and weight is a measure of the gravitational pull force suffered by the object</em>. Indeed, the mass is determined by the number of atoms of the substance, but weight is the force of attraction from Earth (or other planet, if the object is in other planet). Mass does not change with the location; weight does.

  • <em>Dalton's atomic model has similarities to the atomic model described by Leucipo and Democritus</em>: sure. This is a hystorical question. Leucippus and Democritus were two Greek phylosophers who believed that the matter was formed by tiny solid particles, the atom.

  • <em>Dalton thought that atoms of the same element could not combine, as they developed mutual repulsion</em>. In the times of Dalton, when he developed the law of multiple proportions, atoms of a same kind were thought to repel each other.
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what is the limiting reactant when 1.50g of lithium and 1.50 g of nitrogen combine to form lithium nitride, a component of advan
PSYCHO15rus [73]
<h3>Answer:</h3>

Limiting reactant is Lithium

<h3>Explanation:</h3>

<u>We are given;</u>

  1. Mass of Lithium as 1.50 g
  2. Mass of nitrogen is 1.50 g

We are required to determine the rate limiting reagent.

  • First, we write the balanced equation for the reaction

6Li(s) + N₂(g) → 2Li₃N

From the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.

  • Second, we determine moles of Lithium and nitrogen given.

Moles = Mass ÷ Molar mass

Moles of Lithium

Molar mass of Li = 6.941 g/mol

Moles of Li = 1.50 g ÷ 6.941 g/mol

                   = 0.216 moles

Moles of nitrogen gas

Molar mass of Nitrogen gas is 28.0 g/mol

Moles of nitrogen gas = 1.50 g ÷ 28.0 g/mol

                                     = 0.054 moles

  • According to the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
  • Therefore, 0.216 moles of lithium will require 0.036 moles (0.216 moles ÷6) of nitrogen gas.
  • On the other hand, 0.054 moles of nitrogen, would require 0.324 moles of Lithium.

Thus, Lithium is the limiting reagent while nitrogen is in excess.

7 0
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Calculate the number of grams of oxygen gas in a 24L container at STP
romanna [79]

There are 34 g of oxygen in the container.

We can use the<em> Ideal Gas Law</em> to solve this problem.

pV = nRT

But n = \frac{m}{M}, so

pV = \frac{m}{M}RT and

m = \frac{pVM}{RT}\\

STP is 0 °C and 1 bar, so

m = \frac{\text{1 bar} \times \text{24 L} \times 32.00 \text{ g}\cdot\text{mol}^{-1}}{\text{0.083 14 } \text{bar}\cdot\text{L}\cdot\text{K}^{-1}\text{mol}^{-1}\times\text{273.15 K} } = \textbf{34 g}\\

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VashaNatasha [74]

Answer:

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Explanation:

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