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Slav-nsk [51]
3 years ago
6

How long does it take for earth to revolve around the sun?

Physics
1 answer:
Vinvika [58]3 years ago
6 0
The period of revolution is called the "year", and equals about 365.2426 days.
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A net force of 2800 N is applied to a 1400 kg automobile at rest. The speed of the automobile after 10 s will be:
Svetach [21]

The speed after 10 s is 20 m/s

<h3>What is the speed after 10 s?</h3>

Given that we have the following;

force = 2800 N

Mass = 1400 kg

time = 10 s

Recall that;

F = ma

F = force

m = mass

a = acceleration

a = F/m

a =  2800 N/1400 kg

a = 2 m/s^2

Now;

v = u + at

v = ??

u = 0 m/s

a= 2 m/s^2

t = 10 s

v = at

v = 2 * 10

v = 20 m/s

Learn more about the speed:brainly.com/question/28224010

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6 0
1 year ago
4.) A hydroelectric dam runs water thru turbines that are connected to
omeli [17]

Answer:

Explanation:

A turbine and generator produce the electricity

"A hydraulic turbine converts the energy of flowing water into mechanical energy. A hydroelectric generator converts this mechanical energy into electricity.

8 0
3 years ago
4. What is the acceleration of a rock if the net
HACTEHA [7]

Answer:

0.75 m/s²

Explanation:

Newton's second law:

∑F = ma

3 N = (4 kg) a

a = 0.75 m/s²

8 0
3 years ago
Write the answer:<br>physics ... i need help ​
Mariana [72]

Answer:

6 gallons

Explanation:

At 30 mph, the fuel mileage is 25 mpg.

After 5 hours, the distance traveled is:

30 mi/hr × 5 hr = 150 mi

The amount of gas used is:

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7 0
3 years ago
A spring of spring constant k is attached to a support at the bottom of a ramp that makes an angle θ with the horizontal. A bloc
Nikitich [7]

Answer:

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

Explanation:

From the law of conservation of energy

Energy lost  by the spring, W=Kinetic energy gained, KE+Potential energy gained, PE+Work done by friction, Fr

0.5kd^{2}=0.5mv^{2}+mgLsin\theta+\mu_{k}mgcos\theta x

x(mgsin\theta+\mu_{k}mgcos\theta)=0.5kd^{2}

x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

The required distance from A to B is x=\frac {kd^{2}}{2(mgsin\theta +\mu_{k}mgcos\theta)}

5 0
3 years ago
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