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disa [49]
2 years ago
11

why is a train more difficult to stop then a rolling ball even if they are traveling at the same speed? URGENT

Physics
1 answer:
zloy xaker [14]2 years ago
5 0
Think of the formula force=mass x acceleration. even though they have the same acceleration, a train has more mass. is that helpful?
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Whitch two options are forms of kinetic energy?
valentina_108 [34]

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7 0
2 years ago
You have a pendulum clock made from a uniform rod of mass M and length L pivoting around one end of the rod. Its frequency is 1
drek231 [11]

The new oscillation frequency of the pendulum clock is 1.14 rad/s.

     

The given parameters;

  • <em>Mass of the pendulum, = M </em>
  • <em>Length of the pendulum, = L</em>
  • <em>Initial angular speed, </em>\omega _i<em> = 1 rad/s</em>

The moment of inertia of the rod about the end is given as;

I_i = \frac{1}{3} ML^2

The moment of inertia of the rod between the middle and the end is calculated as;

I_f = \int\limits^L_{L/2} {r^2\frac{M}{L} } \, dr = \frac{M}{3L} [r^3]^L_{L/2} =  \frac{M}{3L} [L^3 - \frac{L^3}{8} ] = \frac{M}{3L} [\frac{7L^3}{8} ]= \frac{7ML^2}{24}

Apply the principle of conservation of angular momentum as shown below;

I _i \omega _i = I _f \omega _f\\\\\frac{ML^2}{3} (1 \ rad/s)= \frac{7ML^2}{24} \times \omega _f\\\\\frac{24 \times ML^2}{3 \times 7 ML^2} (1 \ rad/s)= \omega _f\\\\1.14 \ rad/s = \omega _f

Thus, the new oscillation frequency of the pendulum clock is 1.14 rad/s.

Learn more about moment of inertia of uniform rod here: brainly.com/question/15648129

3 0
2 years ago
Which of the following is NOT true regarding the far side of the moon:
frutty [35]
It contains no large maria
8 0
3 years ago
Cross section of a solid circular rod is subject to a torque of t = 2.7 kn⋅m . if the diameter of the rod is d = 8 cm , what is
polet [3.4K]
Shear Stress= Force along the tangent/ Area
= 2700/π*r^2
=2700/3.14*16
=54
3 0
3 years ago
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