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Greeley [361]
4 years ago
14

Explain why is not advisable to use small values of I in performing an experiment on refraction through a glass prism?

Physics
2 answers:
Svetradugi [14.3K]4 years ago
6 0
Explain<span> why it is </span>not advisable to use small values<span> of incident ray in </span>performing experiment<span> on the</span>refraction through a glass prism<span>.</span>
Colt1911 [192]4 years ago
3 0

Answer:

Explanation:

Prism is a glass object that is used to study the pattern of refraction.

During this experiment it is not advised to used small values of incident angle , as when a small amount of incident ray is passed the refracted pattern observed at the end will not provide satisfactory results.

The amount of light that comes out of prism which is the refracted light will also be small hence study of complete refracted pattern will not be possible.

The small incident angle will give rise to more errors in measurement.

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Communicating results allows scientists to learn from each other's results.
sveta [45]

True, scientists often talk to each other to figure out if their results were similar and what they could have done better.

Although, talking to other scientists does have risks, other scientists could copy your work and further better it.

So, your final answer is TRUE, sorry for the long answer, I needed to have a word count about 20 characters and then I got carried away! lol

3 0
3 years ago
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Which quantities are scalars?
Fofino [41]

Answer:

A and B

Explanation:

Because both of them have only magnitude not direction.

7 0
3 years ago
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Part of one row of the periodic table is shown. 4 blue boxes in a row. The first has S n at the center and 50 above with tin and
nydimaria [60]

Answer:

Atoms of tellurium (Te) have the greatest average number of neutrons equal to 76.

Explanation:

In the periodic table, Elements are represented with their respected symbols. Above the symbol is the elements atomic number which is equal to the number of protons in each atom. Below the symbol is the mass number of that element which is roughly equal to the sum of neutrons and protons of that atom.

To calculate the number of neutrons we can take the difference of Atomic number and mass number:

Number of neutrons = mass number - atomic number

<u>- Tin:</u>

Atomic number = 50

Mass number = 119

Number of neutrons = mass number - atomic number = 119 - 50

Number of neutrons = 69

<u>- Antimony(Sb):</u>

Atomic number = 51

Mass number = 122

Number of neutrons = mass number - atomic number = 122 - 51

Number of neutrons = 71

<u>- Tellurium(Te):</u>

Atomic number = 52

Mass number = 128

Number of neutrons = mass number - atomic number = 128 - 52

Number of neutrons = <u>76</u>

<u>- Iodine(I):</u>

Atomic number = 53

Mass number = 127

Number of neutrons = mass number - atomic number = 127 - 53

Number of neutrons = 74

Here, the greatest number of neutrons is for the atoms of Tellurium(Te).

7 0
3 years ago
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Small cubes that are 10 cm on a side and larger ones that are 12 cm on a side are submerged in water. Cubes A and B are made of
Digiron [165]

Answer

given,

given,

small cube side = 10 cm

larger cube side = 12 cm

density of steel = 7 g/cm³

density of aluminium = 2.7 g/cm³

density of the water (ρ₁)= 1 g/cm³

Cube A and B made of steel

buoyant force of Cube A

 B₁ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube B

 B₂ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force of Cube C

 B₃ = ρ₁ V g = 1 x 10 x 10 x 10 x g=  1000 g

for cube D

 B₄ = ρ₁ V g = 1 x 12 x 12 x 12 x g=  1728 g

buoyant force acting on the cube depends on the density of the fluid

hence,

B₂ = B₄  > B₁ = B₃

 

8 0
3 years ago
It is determined that a certain wave of infrared light has a wavelength of 8.45 mm. Given that c=2.99 ×108 m/s, what is the freq
irina [24]

Answer:

The frequency of infrared wave is 35.385 GHz

Explanation:

Given data:

Wavelength of infrared light = 8.45 mm = 8.45 x 10^{-3} m

Velocity of infrared light = 2.99 x 10^{8} m/s

To find: frequency of the infrared wave = ?

We know that the wavelength and frequency are inversely proportional and the formula to derive frequency with velocity and wavelength is:

c = μλ, where

c is velocity of light

μ is frequency of light

λ is wavelength of light

Hence the frequency of light  μ = c/λ

                                                     = \frac{2.99 x 10^{8} m/s }{8.45 x 10^{-3}m }

                                                     = \frac{299}{8.45} x 10^{9} s^{-1}

                                                     =  35.385  x  10^{9} Hz   (since 1 s^{-1} = 1 Hz)

                                                     = 35.385 GHz

6 0
4 years ago
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