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2 answers:
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Answer:
Tension in the cable is T = 16653.32 N
Explanation:
Give data:
Cross section Area A = 1.3 m^2
Drag coefficient CD = 1.2
Velocity V = 4.3 m/s
Angle made by cable with horizontal =30 degree
Density
Drag force FD is given as
Drag force = 14422.2 N acting opposite to the motion
As cable made angle of 30 degree with horizontal thus horizontal component is take into action to calculate drag force
TCos30 = F_D
T = 16653.32 N
Answer:
a= 1.81 m/s²
Explanation:
Ratio of the weights on both surfaces can be calculated as,
=
Here;
Wa is the weight on the asteroid, is weight on earth,
m is mass of pack, a is acceleration due to an asteroid and
g is acceleration due to gravity.
Rearrange above equation for a,
a=g ()
Substitute 3.24 N for Wa, 17.5 N for ,
9.81 m/s² for g in the above equation,
a= 9.81()
a= 1.81 m/s²