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dimulka [17.4K]
3 years ago
8

Does a larger net force always produce a larger change in kinetic energy than a smaller net force? Explain. Yes. Kinetic energy

is directly proportional to the force applied. Yes. A larger net force will result in a larger change in velocity, and thus a larger change in kinetic energy. No. Work depends on the force and on the displacement over which it acts. No. A larger net force always produces a smaller change in kinetic energy.
Physics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

Yes.

Explanation:

According to Newton's second law, acceleration of an object is directly proportional to the net force acting on the object.

Here mass of the object in both the cases is the same.

So, acceleration is greater in the case of larger net forces. Further, larger acceleration means larger velocity.

Now, Kinetic energy = \frac{1}{2}mv^2

so, the object with larger velocity will have greater kinetic energy.

So, the difference in kinetic energy for the larger force will larger.

Therefore, larger net force produces a larger change in kinetic energy than a smaller net force.

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What time period did fish develop
marysya [2.9K]

Answer:

They developed during the Cambrian time period, which was around 530 million years ago.

Explanation:

Hope this Helps!

5 0
4 years ago
In Millikan's experiment, an oil drop of radius 1.362 μm and density 0.888 g/cm3 is suspended in chamber C when a downward-point
Misha Larkins [42]

Answer:

The charge on the oil drop is 3e

Explanation:

F = qE

Where;

F is the applied force in Newton

E is the electric field potential N/C

q is charge in C

Given;

Radius, r = 1.362 μm = 1.362 X 10⁻⁶ m

density, ρ = 0.888 g/cm³ = 0.888 X 10³ kg/m³

Electric field potential = 1.92 ✕ 10⁵ N/C

F =mg

mass of the oil drop = density, ρ  X volume of the oil drop

volume of the oil drop (spherical) =  (4/3)πr³ = 1.3333π(1.362 X 10⁻⁶)³

⇒ volume of the oil drop = 10.584 X 10⁻¹⁸ m³

mass of the oil drop = 0.888 X 10³ (kg/m³) X 10.584 X 10⁻¹⁸ (m³)

⇒ mass of the oil drop = 9.399 X 10⁻¹⁵ kg

⇒ F =mg = 9.399 X 10⁻¹⁵ kg X 9.8 = 9.21 X10⁻¹⁴ N

F = qE

q = F/E

q = (9.21 X10⁻¹⁴)/(1.92 ✕ 10⁵) = 4.797 X 10⁻¹⁹ C

In terms of e

1e = 1.6 X10⁻¹⁹ C

=  (4.797 X 10⁻¹⁹ C)/(1.6 X10⁻¹⁹ C) = 3e

Therefore, the charge on the oil drop is 3e

7 0
3 years ago
A jet airliner moving initially at 889 mph
Eduardwww [97]

Answer:

1500 mph

Explanation:

Take east to be +x and north to be +y.

The x component of the velocity is:

vₓ = 889 cos 0° + 830 cos 59°

vₓ = 1316.5 mph

The y component of the velocity is:

vᵧ = 889 sin 0° + 830 sin 59°

vᵧ = 711.4 mph

The speed is found with Pythagorean theorem:

v² = vₓ² + vᵧ²

v² = (1316.5 mph)² + (711.4 mph)²

v = 1496 mph

Rounded to two significant figures, the jet's speed relative to the ground is 1500 mph.

8 0
4 years ago
What is the frequency of a sound wave with a wavelength of 0.04 meter in air? What type of wave is
Viktor [21]
8500 Hz and Longitudinal


Speed = frequency x wavelength

Speed of sound at 20 degrees Celsius is approximately 340 m/s
4 0
3 years ago
Read 2 more answers
The table shows the diameters of the planets in our solar system. Assume that a basketball whose diameter is 25
tino4ka555 [31]

Answer:

Mercury:

.85

pea

Venus:

2.1

gumball

Earth:

2.2

gumball

Mars:

1.2

marble

Uranus:

9

grapefruit

Neptune:

8.6

softball

Explanation:

I have no clue if I'm right but hopefully, I am

3 0
2 years ago
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