1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
andreyandreev [35.5K]
3 years ago
14

To go to a beach party 600 yd away, you kayak against the ocean current for 2 h. The trip back takes 1 h. Write and solve a syst

em of equations to find your paddling speed, x, in still water. Find the speed of the ocean current, y.
Mathematics
1 answer:
Mice21 [21]3 years ago
8 0

Answer: the paddling speed is 450 yards per hour.

The speed of the ocean current is 150 yards per hour.

Step-by-step explanation:

Let x represent the paddling speed.

Let y represent the speed of the ocean current.

To go to a beach party 600 yd away, you kayak against the ocean current for 2 h. This means that the total speed at which you kayaked is (x - y) yards per hour.

Distance = speed × time.

Distance travelled while going to the party is expressed as

600 = 2(x - y)

Dividing through by 2, it becomes

300 = x - y - - - - - - - - - - -1

The trip back takes 1 h. Assuming you traveled with the ocean current. The total speed at which you returned is (x + y) yards per hour. Distance travelled while going to the party is expressed as

600 = 1(x + y)

600 = x + y - - - - - - - - - -2

Adding equation 1 to equation 2, it becomes

900 = 2x

x = 900/2

x = 450 yards per hour

Substituting x = 450 into equation 2, it becomes

600 = 450 + y

y = 600 - 450

y = 150 yards per hour

You might be interested in
Michelle can run 5.44 miles in 68 minutes. What is Michelle's average speed, in miles per minute?
uranmaximum [27]
5.44 miles/68 minutes=
.08 miles/minute
7 0
3 years ago
Read 2 more answers
(8.18x10^-6)(1.15x10^-5)
ladessa [460]

Answer:

9.407x10-11

Step-by-step explanation:

8.18(9.407x(10)−11)10−6(1.15(9.407x(10)−11)10−5)

8.18(9.407x(10)−11)10−6(1.15(9.407x(10)−11)10−5)

8 0
3 years ago
Read 2 more answers
Factor: 4x^2-12x+9=0
Andreas93 [3]
Use formula a^2-2ab+b^2=(a-b)^2

4x^2-12x+9
\\(2x)^2-2(2x)(3)+3^2
\\(2x-3)^2
6 0
3 years ago
Read 2 more answers
Use distributive property to simplify (0.32x+5.3)+(0.5x+5.6)+(0.03x+0.2)
Serhud [2]

the answer is

.85x+11.1

6 0
4 years ago
Read 2 more answers
#89 will give brainliest for best answer!​
Lady_Fox [76]

Answer:

Median: 11

Range: 12

25th Percentile: 9

75th Percentile: 14

Interquartile Range: 5

Step-by-step explanation:

The median is the line in the 'middle' of the box. The range is the largest number minus the smallest number. 25th Percentile is the first line of the box, 75th is 3rd line. IQR is the 75th Percentile - 25th Percentile.

Hope this helps! :)

6 0
2 years ago
Other questions:
  • Simplify the expression 12k-2+6k<br><br> A. 16k2<br> B. 10k+6<br> C. 18k-2<br> D. 16k
    15·2 answers
  • Help ! and please explain it (: ​
    10·1 answer
  • Number d plz solve it
    12·1 answer
  • A staff member at UF's Wellness Center is interested in seeing if a new stress reduction program will lower employees high blood
    15·1 answer
  • The number of games, g, to be played with n teams can be written by the following equation: g=n^2-n if there are to be 132 games
    7·1 answer
  • The measures of two interior angles of a triangle are 45° and 53°. What is the measure of the third interior angle of the triang
    6·1 answer
  • A spherical balloon is inflated with gas at a rate of 500 cubic centimeters per minute. Find the rates of change of the radius w
    10·1 answer
  • PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
    6·1 answer
  • What is the length of ST¯¯¯¯¯? Enter your answer as a decimal in the box. Round your final answer to the nearest hundredth. in.
    5·2 answers
  • What is the result of subtracting the second equation from the first? <br> -2x+y = 0<br> -7x+3y = 2
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!