The above question is incomplete, here is the complete question:
Calculate the standard molar enthalpy of formation of NO(g) from the following data at 298 K:
Answer:
The standard molar enthalpy of formation of NO is 90.25 kJ/mol.
Explanation:
To calculate the standard molar enthalpy of formation
...[3]
Using Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.
[1] - [2] = [3]
According to reaction [3], 1 mole of nitrogen gas and 1 mole of oxygen gas gives 2 mole of nitrogen monoxide, So, the standard molar enthalpy of formation of 1 mole of NO gas :
=
Answer:
- CFJA17
- THZ561
- GJA561
- GH68
- N461
- DG56
- BSJ57
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Answer:
Gas laws, Laws that relate the pressure, volume, and temperature of a gas. ... These two laws can be combined to form a single generalization of the behavior of gases known as an equation of state, PV = nRT, where n is the number of gram-moles of a gas and R is called the universal gas constant.
Explanation:
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Answer:
c. 1, 3 and 4
Explanation:
Isotopes of the same element have the same number of protons. Isotopes 1, 3 and 4 all have an atomic number of 92 meaning they have the same amount of protons (92 protons) and therefore belong to the same element.
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