When we have the balanced reaction equation is:
H2(g) + CO2(g) ↔ H2O(g) + CO (g)
a) first, to calculate ΔG° for the reaction:
we will use this formula:
ΔG° = -RT㏑Kp
when R is R- rydberg constant = 8.314J/mol.K
and T is the temperature in Kelvin = 2000 K
and Kp = 4.4
so, by substitution:
ΔG° = - 8.314 *2000 *㏑4.4
= - 24624 J/mol = - 24.6 KJ/mol
b) to calculate ΔG so, we will use this formula:
ΔG = ΔG° + RT㏑Qp
So we need first, to get Qp from the reaction equation:
when Qp = P products / P reactants
= PH2O*PCO / PH2 * PCO2
= (0.66 atm * 1.2 atm) / (0.25 * 0.78)
= 4.1
so by substitution:
ΔG = -24624 + 8.314*2000*㏑4.1
= -1162 J/mol = - 1.16 KJ/mol
Answer:
Explanation:
Here, we want to calculate the number of moles of methane in the container
From the ideal gas law:
where:
P is the pressure inside the container which is 3 atm
V is the volume of the container which is 2 L
R is the molar gas constant which is 0.0821 Latm/mol.k
T is the temperature in Kelvin (we convert the temperature in Celsius by adding 273 : 273 + 77 = 350 K)
n is the number of moles that we want to calculate
Substituting the values, we have it that:
Answer:
- The NaCl solution will have higher boiling point.
Explanation:
- C2H6O2 is a molecular substance. Meaning that when it dissolves it will remain this way:
C2H6O2 ---------> C6H12O6 (aq)
- Sodiumchloride (NaCl) is an ionic substance. Meaning that when it dissolves, it will create ions:
NaCl(s)-------> Na+(aq) + Cl- (aq)
Conclusion:
- NaCl is an ionic compound and C2H6O2 is a molecular compound. Ionic compounds have higher boiling points than molecular compounds. Therefore, NaCl will have the higher boiling point.
A.) Most reactive non-metals
