Answer:
Explanation:
According to the free body diagram, in this case, we have:
Recall that the force of friction is given by:
Replacing and solving for the coefficient of kinetic friction:
We have an uniformly accelerated motion. Thus, the acceleration is defined as:
Finally, we calculate :
Answer:
The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Explanation:
Given that,
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.
The speed of sound in air is 343 m/s.
To find,
The wavelength range for the corresponding frequency.
Solution,
The speed of sound is given by the following relation as :
Wavelength for f = 45 Hz is,
Wavelength for f = 375 Hz is,
So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.