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Colt1911 [192]
3 years ago
14

Which one of the following statements is true: The reactive power is the power dissipated in the form of heat by the network. Th

e reactive power is the power delivered to a load without considering the effects of the power-factor angle of the load. The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load. The real power is the power associated with reactive elements that provides a measure of the energy associated with setting up the magnetic and electric fields.
Physics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load

Explanation:

If I and V are the current and voltage across the load, the apparent power, = IV

Since,

apparent power = active power + reactive power

active power = IVcosФ

reactive power = IVsinФ

So, IV = IVcosФ + IVsinФ

where I = current, V = voltage and Ф = power factor angle.

We see that the apparent power is the product of the current, I and the Voltage, V without considering the power factor angle of the load.

So, <u>the apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load.</u>

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Cottage and Small Industries Development Committee to organize National Industrial Goods and Technology Expo

By Glocal Khabar - 2368 0

National Industrial Goods and Technology Expo- Glocal Khabar

Kathmandu, February 19, 2018: Cottage and Small Industries Development Committee is set to organize the twenty-ninth edition of National Industrial Goods and Technology Expo from March 23, 2018 at Bhrikutimandap, Kathmandu.

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3 years ago
A 1000.0 kg truck accelerates from 20.0 m/s to 25.0 m/s over a distance of 300.0 m. What is the average net force on the truck?
choli [55]

Answer:

The average net force on the truck is 375 Newtons.

Explanation:

Using Newton's 3rd equation of motion, we have :

v^{2} - u^{2} = 2×a×s

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u = initial velocity = 20 m/s

a = acceleration

s = distance traveled = 300 m

Using these values in the above equation, we get acceleration = 0.375 m/s^{2}

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Equipotential surface are those surfaces that have the same potential at any point on the surface. Thus the potential difference at any point on the surface is zero due to same potential.

Any charge particle on this surface will move in a perpendicular direction to the Coulombian force. No work is done by the force on a particle moving on an equipotential surface.

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