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Colt1911 [192]
3 years ago
14

Which one of the following statements is true: The reactive power is the power dissipated in the form of heat by the network. Th

e reactive power is the power delivered to a load without considering the effects of the power-factor angle of the load. The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load. The real power is the power associated with reactive elements that provides a measure of the energy associated with setting up the magnetic and electric fields.
Physics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load

Explanation:

If I and V are the current and voltage across the load, the apparent power, = IV

Since,

apparent power = active power + reactive power

active power = IVcosФ

reactive power = IVsinФ

So, IV = IVcosФ + IVsinФ

where I = current, V = voltage and Ф = power factor angle.

We see that the apparent power is the product of the current, I and the Voltage, V without considering the power factor angle of the load.

So, <u>the apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load.</u>

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a metal bar 70cm long and 4.00 kg in mass supported on two knief -edge placed 10 cm from each end. a 6.00 kg weight is suspended
Klio2033 [76]
First, you make a diagram of all the forces acting on the system. This is shown in the figure. We have to determine F1 and F4. Let's do a momentum balance. Momentum is conserved so the summation of all momentum is equal to zero. Momentum is force*distance.

To determine F1: (reference is F4, so F4=0)

∑Momentum = 0 = -F2 - F3 + F1
0 = (-4 kg)(9.81 m/s2)(0.25m)-(6kg)(9.81 m/s2)(0.5-0.3m)+F1(0.5-0.1m)
F1 = 53.96 N (left knife-edge)

To determine F4: (reference is F1, so F1=0)

∑Momentum = 0 = -F2 - F3 + F4
0 = (-4 kg)(9.81 m/s2)(0.25m)-(6kg)(9.81 m/s2)(0.5-0.2m)+F4(0.5-0.1m)
F4 = 68.67 N (right knife-edge) 


4 0
3 years ago
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How do you know if you have all the forces needed for a FBD?
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Two firefighters are trying to break through a door. One firefighter is heavy, and the other is light. If they run at the same s
frez [133]

Answer:

The Heavier Firefighter

Explanation:

Generally, more massive objects will have more intertia than less massive objects.  As such it takes more force to halt a more massive object if its moving at the same speed as a smaller object. This can also be thought of in the context of Newton's second law. The more force needed to accelerate an object means the more force the object will have.

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3 years ago
A small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal
Gemiola [76]

Answer:

Time taken, T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}

Explanation:

It is given that, a small metal ball is suspended from the ceiling by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread’s trajectory describes a cone as shown in attached figure.

From the figure,

The sum of forces in y direction is :

T\ cos\theta-mg=0

T=\dfrac{mg}{cos\theta}

Sum of forces in x direction,

T\ sin\theta=\dfrac{mv^2}{r}

mg\ tan\theta=\dfrac{mv^2}{r}.............(1)

Also, r=l\ sin\theta

Equation (1) becomes :

mg\ tan\theta=\dfrac{mv^2}{l\ sin\theta}

v=\sqrt{gl\ tan\theta.sin\theta}...............(2)

Let t is the time taken for the ball to rotate once around the axis. It is given by :

T=\dfrac{2\pi r}{v}

Put the value of T from equation (2) to the above expression:

T=\dfrac{2\pi r}{\sqrt{gl\ tan\theta.sin\theta}}

T=\dfrac{2\pi l\ sin\theta}{\sqrt{gl\ tan\theta.sin\theta}}

On solving above equation :

T=2\pi \sqrt{\dfrac{l\ cos\theta}{g}}

Hence, this is the required solution.

4 0
3 years ago
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