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Colt1911 [192]
3 years ago
14

Which one of the following statements is true: The reactive power is the power dissipated in the form of heat by the network. Th

e reactive power is the power delivered to a load without considering the effects of the power-factor angle of the load. The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load. The real power is the power associated with reactive elements that provides a measure of the energy associated with setting up the magnetic and electric fields.
Physics
1 answer:
Ksju [112]3 years ago
4 0

Answer:

The apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load

Explanation:

If I and V are the current and voltage across the load, the apparent power, = IV

Since,

apparent power = active power + reactive power

active power = IVcosФ

reactive power = IVsinФ

So, IV = IVcosФ + IVsinФ

where I = current, V = voltage and Ф = power factor angle.

We see that the apparent power is the product of the current, I and the Voltage, V without considering the power factor angle of the load.

So, <u>the apparent power is the power delivered to a load without considering the effects of the power-factor angle of the load.</u>

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How much power is needed to lift a 20-kg object to a height of 4.0 m in 2.5 seconds?
4vir4ik [10]

Answer:

313.92w

Explanation:

Formula for power:

P=W/∆t = Fv

Givens:

m=20kg

∆y=4.0m

∆t=2.5s

a=9.81m/s²

In order to find power, we first need to solve for work.

W=Fd (force*displacement), f=mg

W=mg∆y

W=(20kg)(9.81m/s²)(4.0m)

W=784.8J

P=W/∆t

P=784.8J/2.5s

P=313.92 watts

5 0
2 years ago
A hockey puck has a mass of 0.107 kg and is at rest. A hockey player makes a shot, exerting a constant force of 28.0 N on the pu
gregori [183]

Answer:

The speed does it head toward the goal = 41.87 \frac{m}{s}

Explanation:

Mass = 0.107 kg

Initial velocity ( u ) = 0

Force (F) = 28 N

Time = 0.16 sec

From newton's second law,  Force  = mass × acceleration

⇒  F = m × a

⇒  28 = 0.107 × a

⇒  a = 261.7 \frac{m}{s^{2} } --------- (1)

This is the value of acceleration.

Final speed of the mass is calculated by the equation V = U + at

⇒ U = 0 because mass in in rest position at start.

⇒ V = a t

Put the values of acceleration and time in above formula we get

⇒ V = 261.7 × 0.16

⇒ V = 41.87 \frac{m}{s}

Therefore the speed does it head toward the goal = 41.87 \frac{m}{s}

5 0
3 years ago
Prove for N/C=Volt/m
Zigmanuir [339]

Answer:

simple, Volt =change in potential energy/Charge

the unit of energy is newton meter (Force*distance)

the unit of charge is coloumb

So, Volt/meter=newton* meter/coloumb*meter

=newton/coloumb (hence proved)

This unit is the potential drop per unit of length in a conductive wire with uniform resistance

7 0
3 years ago
Please help with the working of this question
Vilka [71]

Answer:

Principle of conservation of linear momentum is state as provided no external force acts on a system of colliding bodies the total linear momentum of the bodies (in a given direction) remains constant

8 0
3 years ago
A charge q moves from point A to point B. The potential energy of the charge at point A is 5.3 _ 10-10 joules and at point is B
stiv31 [10]
The change in electric potential energy will be converted to kinetic energy; thus:
K.E = 5.3 x 10⁻¹⁰ - 3.1 x 10⁻¹⁰
K.E = 2.2 x 10⁻¹⁰ Joules
Option D is correct.
7 0
3 years ago
Read 2 more answers
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