The net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).
<h3>
Net electric force on the charges</h3>
The net electric force on the charges is calculated as follows;
F = kq₁q₂/r²
where;
- k is coulomb's constant
- q₁ and q₂ are the charges
- r is the distance between the charges
<h3>Distance between the charges</h3>
![|r| = \sqrt{(x_2-x_1)^2+ (y_2-y_1)^2} \\\\|r| = \sqrt{(-4--4)^2+ (0--3)^2} \\\\|r| = \sqrt{(0)^2 + (3)^2} \\\\|r| = 3 \ units](https://tex.z-dn.net/?f=%7Cr%7C%20%3D%20%5Csqrt%7B%28x_2-x_1%29%5E2%2B%20%28y_2-y_1%29%5E2%7D%20%5C%5C%5C%5C%7Cr%7C%20%3D%20%5Csqrt%7B%28-4--4%29%5E2%2B%20%280--3%29%5E2%7D%20%5C%5C%5C%5C%7Cr%7C%20%3D%20%5Csqrt%7B%280%29%5E2%20%2B%20%283%29%5E2%7D%20%5C%5C%5C%5C%7Cr%7C%20%3D%203%20%5C%20units)
![F_{net} = \frac{kq_1q_2}{3^2} \\\\F_{net} = \frac{1}{9} (kq_1q_2) , \ N](https://tex.z-dn.net/?f=F_%7Bnet%7D%20%3D%20%5Cfrac%7Bkq_1q_2%7D%7B3%5E2%7D%20%5C%5C%5C%5CF_%7Bnet%7D%20%3D%20%5Cfrac%7B1%7D%7B9%7D%20%28kq_1q_2%29%20%2C%20%5C%20%20N)
Thus, the net electric force acting on a positive test charge at the origin is determined as ¹/₉(kq₁q₂).
Learn more about electric force here: brainly.com/question/17692887
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Answer:
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Answer: Speed = 4 m/s
Explanation:
The parameters given are
Mass M = 60 kg
Height h = 0.8 m
Acceleration due to gravity g= 10 m/s2
Before the man jumps, he will be experiencing potential energy at the top of the table.
P.E = mgh
Substitute all the parameters into the formula
P.E = 60 × 9.8 × 0.8
P.E = 470.4 J
As he jumped from the table and hit the ground, the whole P.E will be converted to kinetic energy according to conservative of energy.
When hitting the ground,
K.E = P.E
Where K.E = 1/2mv^2
Substitute m and 470.4 into the formula
470.4 = 1/2 × 60 × V^2
V^2 = 470.4/30
V^2 = 15.68
V = square root (15.68)
V = 3.959 m/s
Therefore, the speed of the man when hitting the ground is approximately 4 m/s
The mass of Jupiter is 1.9 x 1027 kg.
well it would be A because 55 degrees is going strait well 75 is going literally straight up